Chapter 11 : Conductors and Insulators

Example No. 11_1 Page No. 329

In [1]:
# What is the area in circular mils of a wire with a diameter of 0.005 in.?

# Given data

Din = 0.005#        # Diameter in Inches=0.005 in.
Dmil = 5#           # Diameter in Mils=5 mil.

# 0.005 in. = 5 mil
# Therefore: Din == Dmil

A = Dmil*Dmil#
print 'The Circular Area = %0.2f cmils'%A
The Circular Area = 25.00 cmils

Example No. 11_2 Page No. 335

In [3]:
# A stranded wire is made up of 16 individual strands of No. 27 gage wire. What is its equivalent gage size in solid wire?

# Given data

N = 16#         # No. of strands=16
A27 = 201.5     # Circular area of No. 27 Guage wire=201.5 cmils

A = N*A27#
print 'The Total Area = %0.2f cmils'%A
The Total Area = 3224.00 cmils

Example No. 11_3 Page No. 340

In [6]:
# How much is the resistance of 100 ft of No. 20 gage copper wire?

# Given data

roh = 10.4#         # roh or specific resistance=10.4 (for Copper)
l = 100.#            # Lenght=100 feet
A = 1022#           # Area of No. 20 Gage=1022 cmil

R = roh*(l/A)#
print 'The Resistance of 100 ft of No. 20 gage Copper Wire = %0.2f ohms'%R
The Resistance of 100 ft of No. 20 gage Copper Wire = 1.02 ohms

Example No. 11_4 Page No. 342

In [7]:
# How much is the resistance of 100 ft of No. 23 gage copper wire?

# Given data

roh = 10.4#         # roh or specific resistance=10.4 (for Copper)
l = 100#            # Lenght=100 feet
A = 509.5#           # Area of No. 23 Gage=509.5 cmil

R = roh*(l/A)#
print 'The Resistance of 100 ft of No. 20 gage Copper Wire = %0.2f ohms'%R
The Resistance of 100 ft of No. 20 gage Copper Wire = 2.04 ohms

Example No. 11_5 Page No. 344

In [9]:
# How much is the resistance of a slab of germanium 0.2 cm long with a crosssectional area of 1 sqcm?

# Given data

roh = 55.0#         # roh or specific resistance=55 (for Germanium)
l = 0.2*10**-2#    # Lenght=100 feet
A = 1.0*10**-2#      # Area=1 sqcm

R = roh*(l/A)#
print 'The Resistance of a Slab of Germanium = %0.2f ohms'%R
The Resistance of a Slab of Germanium = 11.00 ohms

Example No. 11_6 Page No. 344

In [11]:
# A tungsten wire has a 14-Ohms R at 20°C. Calculate its resistance at 120°C.

# Given data

Tmax = 120.#         # Temp(max)=120 degree Centigrates
Tmin = 20.#          # Temp(min)=20 degree Centigrates
Ro = 14.#            # Wire Resistance=14 Ohms
alpha = 0.005#      # Aplha=0.005 (for Tungsten)

delta = Tmax-Tmin#

Rt = Ro+Ro*(alpha*delta)#
print 'The Resistance at 120°C = %0.2f ohms'%Rt
The Resistance at 120°C = 21.00 ohms