Chapter6 One Component Systems

Example 6.1, Page no.26

import math
#initialisation of variables    
G=28.6      #in gms
R=0.08205   #l−atm moleˆ−1 degˆ−1
T=30        #in Celsius
M=153.8     #in gms
v=20.01     #in litres
#CALCULATIONS
p=G*R*(273.1+T)*760/(M*v)
p1=p/(1+(p/760))
#RESULTS
p=round(p,3)
p1=round(p1,3)
print 'vapour pressure using ideal gas =',p,'mm'
print 'vapour pressure using equation =',p1,'mm'

vapour pressure using ideal gas = 175.647 mm
vapour pressure using equation = 142.673 mm

Example 6.2, Page no.27

import math
#initialisation of variables  
T=100       #in Celsius
Vv=30.199   #in l moleˆ−1
Vl=0.01878  #in l moleˆ−1
H=539.7     #in cal gˆ−1
m=18.01     #in g moleˆ−1
R=0.04129   #in l−atm cal ˆ−1
#CALCULATIONS
r=H*m*R*760/((273.1+T)*(Vv-Vl))
r1=1/r
#RESULTS
r1=round(r1,2)
print 'change in boling point of water per mm =',r1, 'deg mmˆ−1'

change in boling point of water per mm = 0.04 deg mmˆ−1

Example 6.3, Page no.27

import math
#initialisation of variables
T=0      #in Celsius
H=79.7   #in cal gˆ−1
vd=-9.06*10**-5        #in l gˆ−1
R=0.04129              #in l−atm cal ˆ−1
#CALCULATIONS
r=H*R/((273.15+T)*vd)
#RESULTS
r=round(r,2)
print 'change in pressure per degree=',r,'atm deg ˆ−1'

change in pressure per degree= -132.98 atm deg ˆ−1

Example 6.4, Page no.27

import math
#initialisation of variables
y1=32.47*10**-4
y2=34.71*10**-4
x1=1.625
x2=1.107
R=1.987         #in cal moleˆ−1 Kˆ−1
#CALCULATIONS
slope=(x2-x1)/(y2-y1)
Hvap=-slope *2.303*R
#RESULTS
Hvap=round(Hvap,2)
print 'Heat of vapourization=',Hvap,'cal moleˆ−1'

Heat of vapourization= 10582.14 cal moleˆ−1

Example 6.5, Page no.28

import math
#initialisation of variables
H=342      #in cal moleˆ−1 gˆ−1
G=21       #in gms
T=60       #in C
R=1.987    #in cal / mol K
#CALCULATIONS
Hvap=G*H
P1=1/(math.exp(Hvap *9/(2.303*R*(273.1+T)*H)))
#RESULTS
print 'molar heat of vapourization =',Hvap,'cal mole ˆ−1'

molar heat of vapourization = 7182 cal mole ˆ−1