Chapter 17: Electrical substations Equipment and Bus bar Layouts

Example 17_1 pgno:329

In [2]:
#given
Isc= 25e3;
i=2.55*Isc;
L=1;
r=0.24;
#solution
F=2.046*(i**2)*10**-5/r;
print"the force on busbar per meter length = kgfper meter",F/1e3

the force on busbar per meter length = kgfper meter 346.461328125