{
 "cells": [
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "# Chapter 6: Bipolar junction Transistors (BJTs)"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "### Example 6.1 page No.215"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 2,
   "metadata": {
    "collapsed": false
   },
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "Emitter current is  0.05 mA\n"
     ]
    }
   ],
   "source": [
    "#Exa 6.1\n",
    "#find the Base current\n",
    "\n",
    "#given data\n",
    "Ic=9.95\t\t\t#in mA\n",
    "Ie=10    \t\t#in mA\n",
    "\n",
    "#Calculation\n",
    "Ib=Ie-Ic\t\t#in mA\n",
    "\n",
    "#result\n",
    "print\"Emitter current is \",Ib,\"mA\""
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "### Example 6.2 page No. 216"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 13,
   "metadata": {
    "collapsed": false
   },
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "Emitter current is 1.0 mA\n",
      "Current amplification factor is   0.98\n",
      "Current gain factor is  49.0\n"
     ]
    }
   ],
   "source": [
    "#Exa 6.2\n",
    "#Find (i)Emitter current (ii)Current amplification factor (iii)Current gain factor \n",
    "\n",
    "#given data\n",
    "IC=0.98\t\t\t#in mA\n",
    "IB=20.0\t\t\t#in uA\n",
    "IB=IB*10**-3\t\t#in mA\n",
    "\n",
    "#Calculation\n",
    "#part (i)\n",
    "IE=IB+IC\t\t#in mA\n",
    "\n",
    "#part (ii)\n",
    "alpha=IC/IE\t\t#unitless\n",
    "#part (iii)\n",
    "Beta=IC/IB\t\t#unitless\n",
    "\n",
    "#Result\n",
    "print\"Emitter current is\",IE,\"mA\"\n",
    "print\"Current amplification factor is  \",alpha\n",
    "print\"Current gain factor is \",Beta"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "### Example 6.3 page No.216"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 10,
   "metadata": {
    "collapsed": false
   },
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "Emitter current is  2.7 mA\n",
      "Collector current is   2.65 mA\n"
     ]
    }
   ],
   "source": [
    "#Exa 6.3\n",
    "#Emitter current and Collector current\n",
    "\n",
    "#given data\n",
    "alfaDC=0.98\t\t\t#unitless\n",
    "ICBO=4\t\t\t\t#in uA\n",
    "ICBO=ICBO*10**-3\t\t#in mA\n",
    "IB=50\t\t\t\t#in uA\n",
    "IB=IB*10**-3\t\t\t#in mA\n",
    "\n",
    "#calculation\n",
    "#Formula : IC=alfaDC*(IB+IC)+ICBO\n",
    "IC=alfaDC*IB/(1-alfaDC)+ICBO/(1-alfaDC)\t#in mA\n",
    "IE=IC+IB\t\t\t#in mA\n",
    "\n",
    "#Result\n",
    "print\"Emitter current is \",IE,\"mA\"\n",
    "print\"Collector current is  \",IC,\"mA\""
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "### Example 6.4 page No. 216"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 9,
   "metadata": {
    "collapsed": false
   },
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "Collector current in mA :  1.09 mA\n"
     ]
    }
   ],
   "source": [
    "#Exa 6.4\n",
    "#Find the collector current\n",
    "\n",
    "#given data\n",
    "IB=10\t\t\t#in uA\n",
    "IB=IB*10**-3\t\t#in mA\n",
    "Beta=99\t\t\t#Unitless\n",
    "ICO=1\t\t\t#in uA\n",
    "ICO=ICO*10**-3\t\t#in mA\n",
    "\n",
    "#calculation\n",
    "#Formula : IC=alfa*(IB+IC)+ICO\n",
    "IC=Beta*IB+(1+Beta)*ICO\t#in mA\n",
    "\n",
    "#Result\n",
    "print\"Collector current in mA : \",IC,\"mA\""
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "### Example 6.5 Page No.216"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 8,
   "metadata": {
    "collapsed": false
   },
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "(i) Current gain factor is 98.0\n",
      " Current amplification factor is 0.99\n",
      " Emitter Current  is 5.05 mA\n",
      "(ii)New level of Ib  is 101.0 micro A\n"
     ]
    }
   ],
   "source": [
    "#Example 6.5\n",
    "#Find (i) alpha , beta  and Ie \n",
    "#(ii)New level of Ib\n",
    "\n",
    "#Given\n",
    "Ic=5*10**-3        #mA collector current\n",
    "Ic_=10*10**-3        #mA collector current\n",
    "Ib=50*10**-6       #mA, Base current\n",
    "Icbo=1*10**-6      #micro A, Current to base open current\n",
    "\n",
    "#Calculation\n",
    "beta=(Ic-Icbo)/(Ib+Icbo)\n",
    "alpha=(beta/(1+beta))\n",
    "Ie=Ib+Ic\n",
    "\n",
    "Ib=(Ic_-(beta+1)*Icbo)/(beta)\n",
    "\n",
    "#Result\n",
    "print\"(i) Current gain factor is\",round(beta,0)\n",
    "print\" Current amplification factor is\",round(alpha,2)\n",
    "print\" Emitter Current  is\",Ie*1000,\"mA\"\n",
    "print\"(ii)New level of Ib  is\",round(Ib*10**6,0),\"micro A\""
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "### Example 6.6 page No. 222"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 18,
   "metadata": {
    "collapsed": false
   },
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "Dynamic input resistance is  40 mohm\n"
     ]
    }
   ],
   "source": [
    "#Exa 6.6\n",
    "#Find the dynamic input resistance\n",
    "\n",
    "#given data\n",
    "delVEB=200\t\t\t#in Volts\n",
    "delIE=5\t\t\t\t#in mA\n",
    "\n",
    "#calculation\n",
    "rin=delVEB/delIE\t\t#in ohm\n",
    "\n",
    "#Result\n",
    "print\"Dynamic input resistance is \",rin,\"mohm\""
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "### Example 6.7 page No. 222"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 32,
   "metadata": {
    "collapsed": false
   },
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "Current gain :  0.979\n",
      "Base current is  0.03 mA\n"
     ]
    }
   ],
   "source": [
    "#Exa 6.7\n",
    "#Determine Current gain and base current\n",
    "\n",
    "\n",
    "#given data\n",
    "ICBO=12.5 \t\t\t#in uA\n",
    "ICBO=ICBO*10**-3 \t\t#in mA\n",
    "IE=2 \t\t\t\t#in mA\n",
    "IC=1.97 \t\t\t#in mA\n",
    "\n",
    "#calculation\n",
    "alfa=(IC-ICBO)/IE \t\t#unitless\n",
    "IB=IE-IC \t\t\t#in mA\n",
    "\n",
    "#result\n",
    "print\"Current gain : \",round(alfa,3)\n",
    "print\"Base current is \",IB,\"mA\""
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "### Example 6.8 page No. 222"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 37,
   "metadata": {
    "collapsed": false
   },
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "Base current ia 0.03 mA\n"
     ]
    }
   ],
   "source": [
    "#Exa 6.8\n",
    "#given data\n",
    "RL=4.0 \t\t\t#in Kohm\n",
    "VL=3.0\t\t\t#in volt\n",
    "alfa=0.96 \t\t#unitless\n",
    "IC=VL/RL \t\t#in mA\n",
    "\n",
    "#calculation\n",
    "IE=IC/alfa \t\t#in mA\n",
    "IB=IE-IC \t\t#in mA\n",
    "\n",
    "#result\n",
    "print\"Base current ia\",round(IB,2),\"mA\""
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "### Example 6.9 page No.227"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 41,
   "metadata": {
    "collapsed": false
   },
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "Collector-emitter Voltage is  9.2 V\n",
      "Base current in uA :  41.67 microA\n"
     ]
    }
   ],
   "source": [
    "#Exa 6.9\n",
    "#Determine Collector emitter voltage and base current\n",
    "\n",
    "#given data\n",
    "VCC=10\t\t\t #in volt\n",
    "RL=800\t\t\t #in ohm\n",
    "VL=0.8\t\t\t #in volt\n",
    "alfa=0.96\t\t #unitless\n",
    "\n",
    "#calculation\n",
    "#VR=IC*RL\n",
    "VCE=VCC-VL \t\t#in Volt\n",
    "IC=VL*1000/RL \t\t#in mA\n",
    "Beta=alfa/(1-alfa) \t#unitless\n",
    "IB=IC/Beta \t\t#in mA\n",
    "\n",
    "#Result\n",
    "print\"Collector-emitter Voltage is \",VCE,\"V\"\n",
    "print\"Base current in uA : \",round(IB*1000,2),\"microA\""
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "### Example 6.10 page No. 227"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 45,
   "metadata": {
    "collapsed": false
   },
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "Collector current is 11.28 mA\n"
     ]
    }
   ],
   "source": [
    "#Exa 6.10\n",
    "#Determine Collector Current\n",
    "\n",
    "#given data\n",
    "alfao=0.98 \t\t#unitless\n",
    "ICO=10 \t\t\t#in uA\n",
    "ICO=ICO*10**-3 \t\t#in mA\n",
    "IB=0.22 \t\t#in mA\n",
    "\n",
    "#calculation\n",
    "IC=(alfao*IB+ICO)/(1-alfao) \t#in mA\n",
    "\n",
    "#result\n",
    "print\"Collector current is\",IC,\"mA\""
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "### Example 6.11 page No. 228"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 47,
   "metadata": {
    "collapsed": false
   },
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "Dynamic input resistance is 250 ohm\n"
     ]
    }
   ],
   "source": [
    "#Exa 6.11\n",
    "#determine Dynamic input resistance \n",
    "\n",
    "#given data\n",
    "delVEB=250 \t\t#in mVolts\n",
    "delIE=1 \t\t#in mA\n",
    "\n",
    "#calculation\n",
    "rin=delVEB/delIE \t#in ohm\n",
    "\n",
    "#result\n",
    "print\"Dynamic input resistance is\",rin,\"ohm\""
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "### Example 6.12 page No. 228"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 49,
   "metadata": {
    "collapsed": false
   },
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "Dynamic output resistance is  6.25 kohm\n"
     ]
    }
   ],
   "source": [
    "#Exa 6.12\n",
    "#Determine Dynamic output resistance\n",
    "\n",
    "#given data\n",
    "delVCE=10-5 \t\t#in Volts\n",
    "delIC=5.8-5\t \t#in mA\n",
    "\n",
    "#calculation\n",
    "rin=delVCE/delIC \t#in Kohm\n",
    "\n",
    "#result\n",
    "print\"Dynamic output resistance is \",rin,\"kohm\""
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "### Example 6.13 page No.232"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 3,
   "metadata": {
    "collapsed": false
   },
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "Operating point Q is ( 5.2 V, 0.6 mA)\n"
     ]
    },
    {
     "data": {
      "image/png": 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ls9mYNmgaRfFF2LvbCc8MZ9nuZVTVVFkdTW5BW9nNUyMEEQ924twJ5uXNo7ii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\n",
      "text/plain": [
       "<matplotlib.figure.Figure at 0x7ff0e0cf5890>"
      ]
     },
     "metadata": {},
     "output_type": "display_data"
    }
   ],
   "source": [
    "#Exa 6.13\n",
    "#Determine operating point\n",
    "%matplotlib inline\n",
    "import matplotlib.pyplot as plt\n",
    "#given data\n",
    "VCC=10 \t\t\t#in volt\n",
    "RC=8 \t\t\t#in Kohm\n",
    "Beta=40 \t\t#unitless\n",
    "IB=15 \t\t\t#in uA\n",
    "IB=IB*10**-3 \t\t#in mA\n",
    "\n",
    "#calculation\n",
    "# For VCE = 0 Volts\n",
    "IC=VCC/RC \t\t#in mA\n",
    "#For IC=0 VCE=VCC=10V :\n",
    "IC=Beta*IB \t\t#in mA\n",
    "VCE=VCC-IC*RC \t\t#in Volts\n",
    "\n",
    "#result\n",
    "print\"Operating point Q is (\",VCE,\"V,\",IC,\"mA)\"\n",
    "\n",
    "#Plot\n",
    "import matplotlib.pyplot as plt\n",
    "fig = plt.figure()\n",
    "ax = fig.add_subplot(111)\n",
    "\n",
    "Vce=[0,10]\n",
    "Ic=[1.25,0]\n",
    "plt.xlabel('Vce,V')\n",
    "plt.ylabel('Ic,mA')\n",
    "ax.plot([5.2], [0.6], 'o')\n",
    "ax.annotate('(5.2V,0.6 mA)', xy=(5.4,0.7))\n",
    "\n",
    "a=plt.plot(Vce,Ic)\n",
    "plt.show(a)"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "### Example 6.14 page No. 232"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 65,
   "metadata": {
    "collapsed": false
   },
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "Operating point at load resistance 5 kohm is ( 6.0 V, 1.2 mA)\n",
      "Operating point at load resistance 7.5 kohm is ( 3.0 V, 1.2 mA)\n"
     ]
    }
   ],
   "source": [
    "#Exa 6.14\n",
    "#How will the Q point change when load resistance will be change\n",
    "\n",
    "#given data \n",
    "Vcc=12 \t\t#in Volt collector supply voltage\n",
    "Ic=1.2         #A, collector current\n",
    "Rl=5            #kohm load resistance\n",
    "\n",
    "#calculation\n",
    "Vce=Vcc-Ic*Rl    #Collector emitter voltage\n",
    "Rl1=7.5\n",
    "Vce1=Vcc-Ic*Rl1\n",
    "\n",
    "#result\n",
    "print\"Operating point at load resistance 5 kohm is (\",Vce,\"V,\",Ic,\"mA)\"\n",
    "print\"Operating point at load resistance 7.5 kohm is (\",Vce1,\"V,\",Ic,\"mA)\""
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "### Example 6.15 Page No.233"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 6,
   "metadata": {
    "collapsed": false
   },
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "Collector to emitter voltage is (Vce) 20 V\n",
      "Collector current at saturation point is (Ic) 6.0 mA\n"
     ]
    },
    {
     "data": {
      "image/png": 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      "text/plain": [
       "<matplotlib.figure.Figure at 0x7ff0b88bb790>"
      ]
     },
     "metadata": {},
     "output_type": "display_data"
    }
   ],
   "source": [
    "#Example 6.15\n",
    "#Given\n",
    "Vcc=20         # V,  collector voltage\n",
    "Rc=3.3*10**3\n",
    "\n",
    "#calculation\n",
    "#Appling kirchoff's Voltage Law\n",
    "Ic=0          #for cut off point\n",
    "Vce=Vcc\n",
    "Ic=Vcc/Rc\n",
    "print \"Collector to emitter voltage is (Vce)\",Vce,\"V\"\n",
    "print \"Collector current at saturation point is (Ic)\",round(Ic*1000,0),\"mA\"\n",
    "\n",
    "#Plot\n",
    "%matplotlib inline\n",
    "import matplotlib.pyplot as plt\n",
    "fig = plt.figure()\n",
    "ax = fig.add_subplot(111)\n",
    "\n",
    "Vce=[0,20]\n",
    "Ic=[6,0]\n",
    "plt.xlabel(\"Vce  (V)\") \n",
    "plt.ylabel(\"Ic  (mA)\") \n",
    "plt.xlim((0,25))\n",
    "plt.ylim((0,8))\n",
    "ax.plot([0], [6], 'o')\n",
    "ax.annotate('(0,6mA)', xy=(0,6))\n",
    "\n",
    "ax.plot([20], [0], 'o')\n",
    "ax.annotate('(20V,0)', xy=(20,0))\n",
    "a=plt.plot(Vce,Ic)\n",
    "plt.show(a)\n",
    "\n"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "### Example 6.16 page No. 233"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 7,
   "metadata": {
    "collapsed": false
   },
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "collector voltage is  -4.5 V\n",
      "Base voltage is  -8.3 V\n"
     ]
    }
   ],
   "source": [
    "#Exa 6.16\n",
    "#find collector voltage and base voltage\n",
    "\n",
    "#given data \n",
    "Beta=45 \t\t\t#Unitless\n",
    "VBE=0.7 \t\t\t#in Volt\n",
    "VCC=0 \t\t\t\t#in Volt\n",
    "RB=10**5 \t\t\t#in ohm\n",
    "RC=1.2*10**3 \t\t\t#in ohm\n",
    "VEE=-9 \t\t\t\t#in Volt\n",
    "\n",
    "#calculation\n",
    "#Applying Kirchoffs Voltage Law in input loop we have\n",
    "#IB*RB+VBE+VEE=0\n",
    "IB=-(VBE+VEE)/RB \t\t#in mA\n",
    "IC=Beta*IB \t\t\t#in mA\n",
    "VC=VCC-IC*RC \t\t\t#in Volts\n",
    "VB=VBE+VEE \t\t\t#in Volts\n",
    "\n",
    "#Result\n",
    "print\"collector voltage is \",round(VC,1),\"V\"\n",
    "print\"Base voltage is \",VB,\"V\""
   ]
  }
 ],
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  "kernelspec": {
   "display_name": "Python 2",
   "language": "python",
   "name": "python2"
  },
  "language_info": {
   "codemirror_mode": {
    "name": "ipython",
    "version": 2
   },
   "file_extension": ".py",
   "mimetype": "text/x-python",
   "name": "python",
   "nbconvert_exporter": "python",
   "pygments_lexer": "ipython2",
   "version": "2.7.6"
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 },
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}