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  {
   "cells": [
    {
     "cell_type": "heading",
     "level": 1,
     "metadata": {},
     "source": [
      "Chapter10:IRREVERSIBILITY AND AVAILABILITY"
     ]
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Ex10.1:pg-386"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "#example 1\n",
      "#Calculating reversible work\n",
      "\n",
      "#Form the Steam Tables,the inlet and the exit state properties are \n",
      "hi=171.95 #initial specific heat of enthalpy in kJ/kg\n",
      "si=0.5705 #initial specific entropy in kJ/kg-K\n",
      "se=2.1341 #final specific entropy in kJ/kg-K\n",
      "he=765.34 #final specific heat of enthalpy in kJ/kg-K\n",
      "m=5 #mass flow rate of feedwater in kg/s\n",
      "q1=900/m #heat added by one of the sources in kJ/kg\n",
      "q2=he-hi-q1 #second heat transfer in kJ/kg\n",
      "To=25+273.3 #Temp. of the surroundings in K\n",
      "T1=100+273.2 #temp. of reservoir of one of the source in K\n",
      "T2=200+273.2 #temp. of reservoir of second source in K\n",
      "wrev=To*(se-si)-(he-hi)+q1*(1-To/T1)+q2*(1-To/T2) #reversible work in kJ/kg\n",
      "print\"\\n Hence, the irreversibility is\",round(wrev,1),\"kJ/kg\"\n"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "\n",
        " Hence, the irreversibility is 62.0 kJ/kg\n"
       ]
      }
     ],
     "prompt_number": 1
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Ex10.2:pg-387"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "#example 2\n",
      "#Calculating reversible work\n",
      "import math\n",
      "#Form the Steam Tables,the inlet and the exit state properties are\n",
      "hi=298.6 #initial specific heat of enthalpy in kJ/kg\n",
      "si=6.8631 #initial specific entropy in kJ/kg-K\n",
      "se=7.4664 #final specific entropy in kJ/kg-K\n",
      "he=544.7 #final specific heat of enthalpy in kJ/kg-K\n",
      "q=-50 #heat lost to surroundings in kJ/kg\n",
      "w=hi-he+q #work in kJ/kg\n",
      "To=25+273.2 #Temp. of the surroundings in K\n",
      "P1=100 #Pressure of ambient air in kPa\n",
      "P2=1000 #Final pressure of air after compression in kPa\n",
      "R=0.287 #Universal gas constant in kJ/kg-K\n",
      "wrev=To*(se-si-R*math.log(P2/P1))-(he-hi)+q*(1-To/To)#reversible work for the given change of state in kJ/kg\n",
      "i=wrev-w #irreversibility in kJ/kg\n",
      "print\"\\n Hence, the irreversibility is\",round(i,1),\"kJ/kg\"\n"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "\n",
        " Hence, the irreversibility is 32.8 kJ/kg\n"
       ]
      }
     ],
     "prompt_number": 3
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Ex10.3:pg-390"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "#example 3\n",
      "#Calculating reversible work and irreversibility\n",
      "\n",
      "#Form the Steam Tables at state 1\n",
      "u1=1243.5 #initial specific internal energy in kJ/kg\n",
      "s1=4.4819 #initial specific entropy in kJ/kg-K\n",
      "v1=28.895 #initial specific volume in m^3/kg\n",
      "v2=2*v1 #final specific volume in kg/m^3\n",
      "u2=u1 #initial specific internal energy in kJ/kg\n",
      "#These two independent properties, v2 and u2 , fix state 2.The final temp. is calculated by interplotation using the data for T2=5C and v2,x=0/3928 and u=948.5 kJ/kg. For T2=10C and v2, x=0.5433 and u=1317 kJ/kg\n",
      "T2=9.1+273.2 #final temp. in K\n",
      "x2=0.513 #quality in final state\n",
      "s2=4.644 #final specific entropy in kJ/kg\n",
      "V1=1 #volume of part of A in m^3\n",
      "m=V1/v1  #mass flow rate in kg/s\n",
      "To=20+273.2 #Room temperature in K\n",
      "Wrev=To*m*(s2-s1) #reversible work in kJ\n",
      "I=Wrev #irreversibility of the process\n",
      "print\"\\n The irreversibility is \",round(I,3),\"kJ\""
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "\n",
        " The irreversibility is  1.645 kJ\n"
       ]
      }
     ],
     "prompt_number": 5
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [],
     "language": "python",
     "metadata": {},
     "outputs": []
    }
   ],
   "metadata": {}
  }
 ]
}