{ "cells": [ { "cell_type": "markdown", "metadata": {}, "source": [ "# Chapter 15:Cold storage" ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "## Example 15.1,PAGE NUMBER:188" ] }, { "cell_type": "code", "execution_count": 1, "metadata": { "collapsed": false }, "outputs": [ { "name": "stdout", "output_type": "stream", "text": [ "\n", "The store volume is 35000 m**3. \n", "The rate of air change is 3.6 per day.\n" ] } ], "source": [ "# Variable declaration\n", "n=2;# The number of two pellet truck doors\n", "m_n=300;#The number of traffic movements per day\n", "t=30;# seconds\n", "\n", "# Calculation\n", "T=n*m_n*t;# The time for the door openings seconds per day \n", "A=2.2*3.2;# The cross sectional area in m**2\n", "v=1;# m/s\n", "I=A*T*v;# The air infiltration in m**3/d\n", "V=50*70*10;# The store volume in m**3\n", "R=I/V;# The rate of air change per day\n", "print\"\\nThe store volume is %5.0f m**3. \\nThe rate of air change is %1.1f per day.\"%(V,R)" ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "## Example 15.2,PAGE NUMBER:188" ] }, { "cell_type": "code", "execution_count": 2, "metadata": { "collapsed": false }, "outputs": [ { "name": "stdout", "output_type": "stream", "text": [ "\n", "The rate of air change without dehumidification is 157500 kg/day. \n", "The cooling load without dehumidification 73.3 kW(calculation error).\n", "\n", "The rate of air change with dehumidification is 36000 kg/day. \n", "The cooling load with dehumidification 18.75 kW.\n" ] } ], "source": [ "# Variable declaration\n", "T=5;# The dry bulb temperature in \n", "R=3.6;# The rate of air change per day\n", "V=35000;# The store volume in m**3\n", "v_spa=0.8;# The specific volume in m**3/kg\n", "q=600;# m**3/h\n", "n=2;# The number of two pellet truck doors\n", "h_1=15.9;# kJ/kg\n", "h_2=-24.3;# kJ/kg\n", "T_1=20;# °C\n", "T_2=-25;# °C\n", "t=24;# Time duration for one day in hours\n", "t_s=24*60*60;# Time duration for one day in seconds\n", "\n", "# Calculation\n", "R_woh=V*R/v_spa;# The rate of air change without dehumidification in kg/day\n", "Q_woh=R_woh*(h_1-h_2)/t_s;# The cooling load without dehumidification in kW\n", "R_wh=q*n*t/v_spa;# The rate of air change with dehumidification in kg/day\n", "Q_wh=R_wh*(T_1-T_2)/t_s;# The cooling load with dehumidification in kW\n", "print\"\\nThe rate of air change without dehumidification is %5.0f kg/day. \\nThe cooling load without dehumidification %2.1f kW(calculation error).\"%(R_woh,Q_woh)\n", "print\"\\nThe rate of air change with dehumidification is %5.0f kg/day. \\nThe cooling load with dehumidification %2.2f kW.\"%(R_wh,Q_wh)\n" ] } ], "metadata": { "kernelspec": { "display_name": "Python 2", "language": "python", "name": "python2" }, "language_info": { "codemirror_mode": { "name": "ipython", "version": 2 }, "file_extension": ".py", "mimetype": "text/x-python", "name": "python", "nbconvert_exporter": "python", "pygments_lexer": "ipython2", "version": "2.7.11" } }, "nbformat": 4, "nbformat_minor": 0 }