{ "cells": [ { "cell_type": "markdown", "metadata": {}, "source": [ "# Chapter 24:Air Movement" ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "## Example 24.1,PAGE NUMBER:281" ] }, { "cell_type": "code", "execution_count": 1, "metadata": { "collapsed": false }, "outputs": [ { "name": "stdout", "output_type": "stream", "text": [ "The density of dry air,rho=0.76 kg/m**3\n" ] } ], "source": [ "# Variable declaration\n", "Z=4500;# Altitude in m\n", "p=575;# mbar barometric pressure\n", "t=-10;# Temperature in °C\n", "\n", "# Calculation\n", "rho=1.2*(p/1013.25)*((273.15+20)/(273.15+t));# The density of dry air in kg/m**3\n", "print\"The density of dry air,rho=%0.2f kg/m**3\"%rho" ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "## Example 24.2,PAGE NUMBER:282" ] }, { "cell_type": "code", "execution_count": 2, "metadata": { "collapsed": false }, "outputs": [ { "name": "stdout", "output_type": "stream", "text": [ "Kinetic energy=29.1 kg/(m s**2)\n" ] } ], "source": [ "# Variable declaration\n", "V=1;# The volume of air in m**3\n", "t=20;# The dry bulb temperature in °C\n", "H=60;# % saturation\n", "p=101.325;# The pressure in kPa\n", "v=7;# The velocity in m/s\n", "v_s=0.8419;# The specific volume in m**3/kg\n", "\n", "# Calculation\n", "m=V/v_s;# Mass in kg\n", "Ke=(m*v**2)/2;# Kinetic energy in kg/(m s**2)\n", "print\"Kinetic energy=%2.1f kg/(m s**2)\"%Ke" ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "## Example 24.3,PAGE NUMBER:296" ] }, { "cell_type": "code", "execution_count": 3, "metadata": { "collapsed": false }, "outputs": [ { "name": "stdout", "output_type": "stream", "text": [ "The amount of Static regain=16.2 Pa\n" ] } ], "source": [ "# Variable declaration\n", "v_e=8;# The entering velocity of air in m/s\n", "v_l=5.5;# The leaving velocity of air in m/s\n", "fl=20;# Friction losses in %\n", "m=1.2;# Masss in kg\n", "\n", "# Calculation\n", "P_e=(m*v_e**2)/2;# Velocity pressure entering expansion in Pa\n", "P_l=(m*v_l**2)/2;# Velocity pressure leaving expansion in Pa\n", "FL=fl*10**-2*(P_e-P_l);# Friction losses in Pa\n", "Sr=(1-(fl*10**-2))*(P_e-P_l);# Static regain in Pa\n", "print\"The amount of Static regain=%2.1f Pa\"%Sr" ] } ], "metadata": { "kernelspec": { "display_name": "Python 2", "language": "python", "name": "python2" }, "language_info": { "codemirror_mode": { "name": "ipython", "version": 2 }, "file_extension": ".py", "mimetype": "text/x-python", "name": "python", "nbconvert_exporter": "python", "pygments_lexer": "ipython2", "version": "2.7.11" } }, "nbformat": 4, "nbformat_minor": 0 }