Chapter-5 Metal semiconductor field effect transistors

Ex 5.6.1 Pg 5-22

In [2]:
#Given : 
VTN=0.7##V
W=45##micro m
L=4##micro m
mu_n=700##cm**2/V-s
t_ox=450##Angstrum
epsilon_ox=3.9*8.85*10**-14##F/cm
VGS=2*VTN##V
Kn=(W*10**-4)*mu_n*epsilon_ox/(2*(L*10**-4)*(t_ox*10**-8))##A/V**2
Kn=Kn*10**3##mA/V**2
print "Kn = %0.3f mA/V**2"%Kn
ID=Kn*(VGS-VTN)**2##A
print "Current = %0.2f mA"%ID
#Answer is wrong in the book. Calculation mistake whle calculating value for Kn.
Kn = 0.302 mA/V**2
Current = 0.15 mA