chapter 07 : Antenna Measurements

Exa 7.1 : page 7.28

In [1]:
#given data :
f=6.0 #in GHz
f=f*10**9 #in Hz
d=10 #in feet
d=3.048 #in meter
c=3*10**8 #in m/s
lamda=c/f #in meters
rmin=2*d**2/lamda #in meters
print "Minimum separation distance = %0.2f m" %rmin

Minimum separation distance = 371.61 m

Exa 7.2 : page 7.28

In [2]:
#given data :
GP=12.5 #unitless
P_dB=23 #in dB
P=10**(P_dB/10) #unitless
G=GP*P #unitless
GdB=GP+P_dB #in dB
print "Gain of large antenna = %0.2f "% GdB
#Note : Answer in the book is wrong.

Gain of large antenna = 35.50

Exa 7.3 : page 7.28

In [5]:
from math import log10
#given data :
print "Open mouth aperture, D = 10*lambda" 
print "Power gain : GP = 6*(D/labda)**2" 
GP=6*10**2 #unitless
GPdB=10*log10(GP)
print "Power gain = %0.1f dB " %GPdB 

Open mouth aperture, D = 10*lambda
Power gain : GP = 6*(D/labda)**2
Power gain = 27.8 dB

Exa 7.4 : page 7.28

In [21]:
#given data :
f=30000. #in MHz
f=f*10**6 #in Hz
d=20 #in feet
d=20*0.3048 #in meter
c=3*10**8 #in m/s
lamda=c/f #in meters
r=2*d**2/lamda #in meters
print "Minimum distance between primary and secondary = %0.2f m" %r
# Answe wrong in the textbook.

Minimum distance between primary and secondary = 7432.24 m

Exa 7.5 : page 7.29

In [23]:
#given data :
f=1.2 #in GHz
f=f*10**9 #in Hz
BWFN=5 #in degree
c=3.0*10**8 #in m/s
lamda=c/f #in meters
D=140*lamda/BWFN #in meters
print "Diameter of a paraboloidal reflector = %0.2f m" %D

Diameter of a paraboloidal reflector = 7.00 m

Exa 7.6 : page 7.29

In [25]:
from math import pi, sqrt, log10
#given data :
f=9.0 #in GHz
f=f*10**9 #in Hz
c=3*10**8 #in m/s
lamda=c/f #in meters
r=35 #in cm
r=r*10**-2 #in meters
Attenuation=9.8 #in dB
#Formula : 10*log10(WT/Wr) = 9.8dB
WTbyWr=10**(Attenuation/10) #unitless
D=(4*pi*r/lamda)*(sqrt(1/WTbyWr)) #unitless
D_dB=10*log10(D) 
print "Gain of the horn = %0.2f dB " %D_dB 

Gain of the horn = 16.30 dB

Exa 7.7 : page 7.29

In [28]:
from math import pi, sqrt, log10
#given data :
ratio = 28 # length:diameter
from sympy import symbols, N
lamda = symbols('lamda')
L = 0.925*lamda
Z = 710+1J*0  # ohm
Zs = 35476/Z  # ohm
D = L/ratio
omega = 2*D
print "omega =",N(omega,2)

omega = 0.066*lamda