Chapter 4 Transistors

Ex 4_1 PG-4.11

In [2]:
from __future__ import division
Ie=12e-3##emitter current
Ic=Ie/1.02##collector current
Ib=Ie-Ic##base current
print "\n Therefore base current is %.0f microA \n"%(Ib*1e6)

 Therefore base current is 235 microA

Ex 4_2 Pg-4.14

In [3]:
from __future__ import division
print "When beta_dc=50 "
beta_dc=50#
alpha_dc=beta_dc/(1+beta_dc)#
print "\n alpha_dc=%.4f \n\n"%(alpha_dc)
print " When beta_dc=190 "
beta_dc=190#
alpha_dc=beta_dc/(1+beta_dc)#
print "\n alpha_dc=%.4f \n\n"%(alpha_dc)
print " When alpha_dc=0.995 "
alpha_dc=0.995#
beta_dc=alpha_dc/(1-alpha_dc)#
print "\n beta_dc=%.0f \n\n"%(beta_dc)
print " When alpha_dc=0.9765 "
alpha_dc=0.9765#
beta_dc=alpha_dc/(1-alpha_dc)#
print "\n beta_dc=%.2f \n"%(beta_dc)

When beta_dc=50 

 alpha_dc=0.9804 


 When beta_dc=190 

 alpha_dc=0.9948 


 When alpha_dc=0.995 

 beta_dc=199 


 When alpha_dc=0.9765 

 beta_dc=41.55

Ex 4_3 Pg-4.15

In [4]:
from __future__ import division
Ib=20e-6#
Ie=0.0064#
beta_dc=Ie/Ib-1#
alpha_dc=beta_dc/(1+beta_dc)#
print "\n beta_dc=%.0f \n \n alpha_dc=%f \n"%(beta_dc,alpha_dc)
Ic=beta_dc*Ib##collector current
print "\n collector current is %.3f mA \n"%(Ic*1e3)

 beta_dc=319 
 
 alpha_dc=0.996875 


 collector current is 6.380 mA

Ex 4_4 PG-4.15

In [5]:
from __future__ import division
Icbo=5e-6##leakage current
Ic=20e-3##collector current
Ie=Ic/0.996##Ic=o.996Ie
alpha_dc=Ic/Ie#
print "\n alpha_dc=%.3f \n"%(alpha_dc)
print "We know that Ic=alpha_dc*Ie+Icbo "
print "Therefore emitter current is Ie=(Ic-Icbo)/alpha_dc"
Ie=(Ic-Icbo)/alpha_dc##emitter current
Ie=Ie*1e3#
print "\n emitter current is %.2f mA"%(Ie)

 alpha_dc=0.996 

We know that Ic=alpha_dc*Ie+Icbo 
Therefore emitter current is Ie=(Ic-Icbo)/alpha_dc

 emitter current is 20.08 mA