# Variable
#(a)
Temp_c=100. ; #[degree Celsius]
# Calculation and Result
Temp_k=Temp_c+273 ; #[K]
print '(a) Temperature in kelvin is %.2f K'%Temp_k
#(b)
Temp_f=(100*(1.8/1)) +32 ; #[degree Fahrenheit]
print ' (b) Temperature in degree Fahrenheit is %.2f '%Temp_f
#(c)
Temp_r= Temp_f + 460 ; #[degree Rankine ]
print ' (c) Temperature in degree Rankine is %.2f '%Temp_r
# Variables
c = 139.1 + (1.56*10**-1)*(-460-32)/1.8 ;
d = (1.56*10**-1)/1.8;
# Calculation
#Now convert c +dTR to (Btu/lb mol*degree R) to get answer of form a + bTR,where
a = c*(454/(1055*1.8)) ;
b = d*(454/(1055*1.8)) ;
# Result
print 'The required answer is %.2f + (%.2e)T Btu/(lb mol*degree R) , where T is in degree R . '%(a,b)