In [1]:

```
from __future__ import division
from math import pi
from sympy import symbols,solve
#Calculating modified reynold's no.
a = 800# #it is in m**2/m**3
Product_rate = 0.5# #it is in g/sec
Reflux_ratio = 8#
Vapour_rate = 4.5# #it is in g/sec
G = (4.5*10**(-3))/((pi/4)*(0.1**2))## units are in kg/m**2.sec
meu = 0.02*10**(-3)# #units are in Ns/m**2
e = 0.72#
Re1 = G/(800*0.28*0.02*10**(-3))#
print"\n The modified reynolds no. is %d"%(Re1)#
x = 4.17/Re1 + 0.29# #x = R1/(pu1**2)
print"\n The value of R1/(pu1**2) is %.3f "%(x)#
l = 16*0.15# #in meters
#Solving the integral integral of(pdP)from Pc toPs =(R1/pu**2)*S*(1-e)*G**2*l/e**3
Pc = symbols('Pc')
y = solve(151.3-(4.73*10**(-5)*(8000**2-Pc**2)))
print"\n The value of Pc is %dN/m**2"%(y[0])#
```