# Chapter 18: Information Theory, Coding And Data Communication¶

## Example 18.1, page no. 591¶

In :
# Variable Declaration
SNR_dB = 32.00                     # Signal to Noise ratio (dB)
f1     = 300.00                    # Lower Limit of Voice Frequency (Hz)
f2     = 3400.0                    # Upper Limit of Voice Frequency (Hz)

# Calculation
import math                        # Math Library
SNR    = pow(10,SNR_dB/10)         # Signal to Noise Ratio
C      = (f2-f1)*math.log(1+SNR,2) # Capacity of Telephone Channel (bps)

# Result
print "The capacity of a standard 4 kHz telephone channel with 32 dB SNR is C =",round(C,1),"bits per second."

The capacity of a standard 4 kHz telephone channel with 32 dB SNR is C = 32956.3 bits per second.


## Example 18.2, page no. 591¶

In :
# Variable Declaration
SNR_dB = 28.00         	          # Signal to Noise ratio (dB)
BW1    = 4.00*pow(10,3)           # System Bandwidth 1 (Hz)
BW2    = 8.00*pow(10,3)           # System Bandwidth 2 (Hz)

# Calculation
import math                       # Math Library
SNR1   = pow(10,SNR_dB/10)        # Signal to Noise Ratio 1
C1     = BW1*math.log(1+SNR1,2)   # Information Carrying Capacity (bps)
SNR2   = pow(10,SNR_dB/10)/2      # Signal to Noise Ratio 2
C2     = BW2*math.log(1+SNR2,2)   # Information Carrying Capacity (bps)

# Result
print "(a) The information carrying capacity of a standard 4 kHz telephone channel with 28 dB SNR is C1 =",round(C1),"bits per second."
print "(b) The information carrying capacity of a standard 8 kHz telephone channel with same signal power as in (a) is C2 =",round(C2),"bits per second."
print "    Also the ratio of the two quantities,   C2/C1 =",round(C2/C1,3)

(a) The information carrying capacity of a standard 4 kHz telephone channel with 28 dB SNR is C1 = 37215.0 bits per second.
(b) The information carrying capacity of a standard 8 kHz telephone channel with same signal power as in (a) is C2 = 66448.0 bits per second.
Also the ratio of the two quantities,   C2/C1 = 1.786