Chapter 6 : Introduction to the dimensional analysis of convection

Example 6.1 page : 116

In [5]:
# Variables
u = 2.08/32.2;                             # vismath.cosity of water at 80degF in slug/ft-hr
rho = 62.4/32.2;                           # density of water in slug/ft**3
d = 2./12;                                  # inner diameter of tube in ft
v = 10.;                                    # average water velocity in ft/sec

# Calculations 
V = 0.0648/1.94
Nre = d*v*3600/V;                      # reynolds number
# 3600 is multiplies to convert sec into hrs

# Results
print "Reynolds Number is %d"%(Nre);

# rounding off error.

Reynolds Number is 179629

Example 6.2 page : 116

In [7]:
# Variables
u = 2.08/32.16;                             # vismath.cosity of water at 80 degF in slug/ft-hr
m = 965000/32.16;                           # mass velocity of water in slug/hr-ft

# Calculations 
d = 1./12;                                   # inner diameter of tube in ft
Nre = m*d/u;                                # reynolds number

# Results
# 3600 is multiplies to convert sec into hrs
print "Reynolds Number is %d"%(Nre);

# book answer is rounded off.

Reynolds Number is 38661