# Given
T_c = 7.2 # critical temperature in K
T = 5.1 # temperature in K
lambda_ = 380 # penetration depth at 0 K in A
#Calculations
lamda = lambda_ * (1 - (T / T_c)**4)**(-1./2)
#Result
print "Penetration depth is %.2f A"%lamda
from math import *
# Given
Hc1 = 1.41e5 # first critical field at 14.1K
Hc2 = 4.205e5 # second critical field at 12.9K
T1 = 14.11 # temperature in K
T2 = 12.9 # temperature in K
T = 4.2 # temperature in K
lambda_ = 380 # penetration depth at 0 K in A
#Calculations
Tc = sqrt((Hc2*T1**2 - Hc1*T2**2) / (Hc2 - Hc1))
H_ = Hc1 / (1 - (T1 / Tc)**2)
Hc = H_ * (1 - (T/Tc)**2)
#Result
print "Transition temperature is %.2f K\nCritical field at temperate at 4.2 k is %.2e A/m"%(Tc,Hc)
from math import *
# Given
d = 1e-3 # diameter of wire in m
T1 = 4.2 # temperature in K
T2 = 7.18 # temperature in K
H_ = 6.51e4 # critical magnetic field at 0 K
#Calculations
r = d / 2
Hc = H_ * (1 - (T1 / T2)**2)
Jc = (2 * pi * r * Hc) / (pi * r**2)
#Result
print "Critical current density is %.3e A/m^2"%Jc
# Given
w = 199.5 # isotopic mass of Hg
Tc = 4.186 # critical temperature in K
w_ = 203.4 # increased isotope mass of Hg
#Calculations
Tc_ = Tc * (w / w_)**(1./2)
#Result
print "Critical temperature is %.4f K"%Tc_
# Given
T_c = 4.2 # critical temperature in K
T = 2.9 # temperature in K
lamda = 57 # penetration depth at 2.9 K in nm
#Calculations
lambda_ = lamda * (1 - (T / T_c)**4)**(1./2)
#Result
print "Penetration depth at 0 K is %.2f nm"%lambda_
# Given
T1 = 2.18 # temperature in first case in K
lambda1 = 16 # penetration depth at 2.18 K in nm
T2 = 8.1 # temperature in second case in K
lambda2 = 96 # penetration depth at 8.1 K in nm
#Calculations
Tc = (((lambda2**2 * T2**4) - (T1**4 * lambda1**2)) / (lambda2**2 - lambda1**2))**(1./4)
#Result
print "Critical temperature is %.2f K"%Tc
# Given
w = 26.91 # isotopic mass of superconducting sample
Tc = 1.19 # first critical temperature in K
w_ = 32.13 # increased isotope mass of superconducting sample
#Calculations
Tc_ = Tc * (w / w_)**(1./2)
#Result
print "Critical temperature is %.3f K"%Tc_
# Given
k = 1.38e-23 # Boltzmann's constant in J/K
h = 6.62e-34 # Planck constant in J sec
Tc = 4.2 # critical temperature of Hg in K
c = 3e8 # speed of light in m/sec
#Calculations
E = 3 * k * Tc
lamda = h * c / E
#Result
print "Energy gap is %.2e eV\nWavelength of photon is %.2e m"%(E/1.6e-19,lamda)