# Chapter 22: Nanopyhsics¶

## Example 22.1, Page 22.13¶

In [1]:
# Given
d = 12e-6 # diameter in m
d_ = 90e-9 # diameter of nanoparticle in m

#Calculations
r = d / 2
r_ = d_ / 2
k = r / 3
k_ = r_ / 3
R = k_ / k

#Result
print "The ratio of the value of Nb/Ns of spherical particle and nanoparticle = %.1e"%R

The ratio of the value of Nb/Ns of spherical particle and nanoparticle = 7.5e-03