Chapter 1 : Properties Of Fluids

Example 1.1 Page No : 4

In [1]:
	
#Initialization of variables
sw = 62.4 	#specific weight of water at ordinary pressure - lb/ft**3
sw2 = 9.81 	#specific weight of water at temperature - kN/m**3
sg = 13.55 	#specific weight of mercury 
g = 32.2   	#ft/s**2
	
#calculations
dwater = sw/g
dwater2 = sw2/(9.81)
Gmercury = sg*sw
Gmercury2 = sg*sw2
dmercury = sg*dwater
dmercury2 = sg*dwater2
	
#Results
print 'Density of water  =  %.2f slugs/ft**3'%(dwater)
print ' Density of water  =  %.2f g/ml'%(dwater2)
print ' Density of mercury  =  %.1f slugs/ft**3'%(dmercury)
print ' Density of mercury  =  %.2f kN/m**3'%(dmercury2)
print ' Specific weight of mercury  =  %d lb/ft**3'%(Gmercury+1)
print ' Specific weight of mercury  =  %d kN/m**3'%(Gmercury2+1)

Density of water  =  1.94 slugs/ft**3
 Density of water  =  1.00 g/ml
 Density of mercury  =  26.3 slugs/ft**3
 Density of mercury  =  13.55 kN/m**3
 Specific weight of mercury  =  846 lb/ft**3
 Specific weight of mercury  =  133 kN/m**3

Example 1.2 Page No : 9

In [1]:
	
#Initialization of variables
T = 460.+100 	#R
P = 15.       	#psia
MW = 32.     	#lb
g = 32.2	    #ft/s**2
ratio = 0.4
	
#calculations
R = 49710./32
d = P*144/(R*T)
Gamma = d*g
volume = 1/d
P2 = P*(1/ratio)**1.4
P2f = P2*144
T2 = P2f*ratio/(d*R) -460
P3 = P/ratio
	
#Results
print ' part a'
print ' Density of oxygen  =  %.5f slug/ft**3'%(d)
print ' Specific weight of oxygen  =  %.2f lb/ft**3'%(Gamma)
print ' Specific volume of oxygen  =  %d ft**3/slug'%(volume+1)
print ' part b'
print ' Final pressure of oxygen  =  %.1f psia '%(P2)
print ' Final Temperature of oxygen  =  %d F '%(T2+2)
print ' part 3'
print ' Final pressure of oxygen  =  %.1f psia '%(P3)
print ' Final Temperature of oxygen  =  %d F '%(T-460)

 part a
 Density of oxygen  =  0.00248 slug/ft**3
 Specific weight of oxygen  =  0.08 lb/ft**3
 Specific volume of oxygen  =  403 ft**3/slug
 part b
 Final pressure of oxygen  =  54.1 psia 
 Final Temperature of oxygen  =  349 F 
 part 3
 Final pressure of oxygen  =  37.5 psia 
 Final Temperature of oxygen  =  100 F

Example 1.3 Page No : 10

In [3]:
	
#Initialization of variables
P = 600.*1000 	#N/m**2
T = 25.     	#C
M = 71. 	    #Kg
	
#calculations
R = 8312/M
d = P/(R*(273+T))
Gamma = d*9.81
v = 1/d

# results
print 'Density of chlorine  =  %.1f kg/m**3'%(d)
print ' Specific weight of chlorine  =  %d N/m**3'%(Gamma+1)
print ' Specific volume of chlorine  =  %.3f m**3/Kg'%(v)

Density of chlorine  =  17.2 kg/m**3
 Specific weight of chlorine  =  169 N/m**3
 Specific volume of chlorine  =  0.058 m**3/Kg