Ch-7, Thermal Power Plants

example7.1 Page 127

pow=100*10**6
calv=6400
threff=0.3
elceff=0.92
kcal=0.239*10**-3
eo=pow*3600
ei=eo/(threff*elceff)
eikc=ei*kcal
colreq=eikc/6400
print " energy output in 1 hour is %eWatt.sec "%eo
print "\n energy input in one hour is %ejoules Watt.sec\n"%ei
print " energy input in 1 hour is %ekcal."%eikc
print "\n coal required is %.3fkg per hour"%colreq

 energy output in 1 hour is 3.600000e+11Watt.sec 

 energy input in one hour is 1.304348e+12joules Watt.sec

 energy input in 1 hour is 3.117391e+08kcal.

 coal required is 48709.239kg per hour