In [1]:

```
# Variables
li = 1.23; #length of melting ice in mm
lf = 18.56; #length of melting ice reading in pressure of 74.24cm of mercury in mm
l = 10.75; #length of melting ice at which temperature to be calculated
mp = 0; #melting point in deg.C
T = 50; #temperature of melting ice at which length to be calculated in deg.C
# Calculations
sp = 100-(76-74.24)/(2.7); #76cm of mercury steam point is 100 deg.C so at 74.24cm of mercury the steam point in deg.C
t = (l-li)*(sp-mp)/(lf-li); #temperature at 10.75mm of melting ice in deg.C
lt = ((T*(lf-li))/(sp-mp))+li; #length of ice at 50 deg.C
# Result
print 'the temperature of melting ice at 10.75mm of hg is %3.2f deg.C \
\nthe length of ice corresponding to 50 deg.C is %3.2f mm of mercury'%(t,lt)
```

In [2]:

```
# Variables
p1 = 23.5; #pressure when immersed in liquid air in cm
p2 = 75.; #pressure when immersed in ice in cm
p3 = 102.4; #pressure when immersed in steam in cm
T = 100.; #boiling point of temperature in deg.C
# Calculations
t = (p1-p2)*T/(p3-p2); #temperature of the liquid air in deg.C
# Result
print 'the temperature of liquid of air is %3.2f deg.C'%(t)
```

In [6]:

```
# Variables
t1 = 283.; #temperature of bulb when pressure is h-2cm of hg in k
t2 = 546.; #temperature of bulb when pressure is h-22cm of hg in k
h1 = 2.; #differnce of mercury level at 283k in cm
h2 = 22.; #differnce of mercury level at 546k in cm
# Calculations
h = ((h2*t1)+(h1*t2))/(t2-t1); #height of the barometer in cm
# Result
print 'height of the barometer is %3.2f cm'%(h)
print "Note : Answer in book is wrong. Please calculate manually and check."
```

In [7]:

```
# Variables
p0 = 76.; #pressure at 0 deg.C in cm of hg
p1 = 228.; #pressure (76+152) at T deg.C in cm of hg
t0 = 273.; #temperature of bulb in K
# Calculations
T = p1*t0/p0; #temperature at 228 cm of hg pressure in K
# Result
print 'the temperature of bulb is %3.2f K'%(T)
```

In [13]:

```
# Variables
t1 = 0; #temperature in deg.C
t2 = 100; #temperature in deg.C
t3 = 208; #temperature in deg.C
r1 = 3.5; #resistance in ohms
r2 = 5.2; #resistance in ohms
r3 = 6.9; #resistance in ohms
r4 = 9.4; #resistance in ohms
# Calculations
tpt = (r3-r1)*100/(r2-r1); #temperature in deg.C
d = round((t3-tpt)/(2.08*1.08),2); #deflection
tp = round((r4-r1)*100/(r2-r1),2); #temperature in deg.C
t6 = (3.5*(((tp/100)**2)-tp/100))+tp; #temperature in deg.C
t7 = (3.5*(((t6/100)**2)-t6/100))+tp; #temperature in deg.C
t8 = (3.5*(((t7/100)**2)-t7/100))+tp; #temperature in deg.C
t9 = (3.5*(((t8/100)**2)-t8/100))+tp; #temperature in deg.C
#Result
print 'the temperature of the bath is %3.2f deg.C'%(t9)
```