Chapter 01 : Energy Band in Solid

Example 1.2, Page No 55

In [1]:
import math
#initialisation of variables

d=0.001     #distance between parallel plate in m
V=1000.0   #applied voltage
q=1.6*(10**-19)     #charge on an electron
m = 9.1*(10**-31)     #mass of electron in kg
#Time taken by electron to reach other side of parallel plate capacitor
E=V/d       #Electric Field in V/m
#Formulae : s = u*t + (a*t^2)/2

#Calculations
a = (q*E)/m     #acceleration on electron in m/s^2
t = (2*d/a)**0.5         #time taken to reach the other side of plate
print("Time taken to reach other side =  %.2f sec " %t)

#Magnitude of force exerted on electron
print('Since the potential is constant the force will be constant between the paltes of capacitor')
F=q*E        #force
print("Force on electron =   %.2f N " %F)
#Velocity of electron at the other plate
#Formulae: v = u + a*t
v = a*t           #velocity at the end of other plate

#Results
print("V =   %.2f m/sec " %V)
Time taken to reach other side =  0.00 sec 
Since the potential is constant the force will be constant between the paltes of capacitor
Force on electron =   0.00 N 
V =   1000.00 m/sec