Chapter 03 : Junction diode characteristics

Example 3.1, Page No 62

In [1]:
import math
#initialisation of variables
Na=10.0**19     #Cm^3
q=1.6*10**-19
Vj=0.94     #V
Nd=10.0**17
e=11.9*8.85*10**-14
A=9.6*10**-8

#Calculations
W=math.sqrt(((2*e)/(q*Nd))*Vj)
Ct=e*A/(W*10**-4)

#Results
print("The transition capacitance is= %.2f fF " %(Ct*10**11))

The transition capacitance is= 9.09 fF

Example 3.3, Page No 67

In [2]:
import math
#initialisation of variables
t=10         #ns lifetime of holes
I=0.1        #mA forward current
n=1
vt=0.026     #V

#Calculations
Cd=(t*I)/(n*vt)

#Results
print("The defusion capicitance is= %.2f pF " %Cd)

The defusion capicitance is= 38.46 pF

Example 3.4, Page No 70

In [3]:
import math
#initialisation of variables
V=10.0
Vb=6.0      # breakdown voltage

vz1=0.1/(0.1+1)*10    #v
vz2=9.0/(9+1)*10    #v

#Calculations
Ir=(V-Vb)/vz1
Il=Vb/vz2
Iz=Ir-Il


#Results
print("The value of Iz is= %.2f mA " %(Iz))

The value of Iz is= 3.73 mA