# CHAPTER 10 - Fundamentals of Metal Casting¶

## EXAMPLE 10.1 - PG NO 252¶

In [3]:
#Example 10.1
#page no. 252
# Given that
#three metal piece being cast have the same volume but different shapes
#shapes are sphere,cube,cylinder(height=diameter)

print("\n #solidification time for various shapes# \n")

#solidification time is inversely proportional to the square of surface area

#for sphere
r=(3./(4.*3.14))**(1./3.)#radius of the sphere from volume of sphere v=(4*3.14*r**3)/3
A=4*3.14*((r)**2)
time1=1./(A)**2.
print'%s %.6f %s' %("\n the solidification time for the sphere is ",time1,"C")

#for cube
a=1#edge of the cube
A=6*a**2
time2=1./(A)**2
print'%s %.6f %s' %("\n the solidification time for the cube is ",time2,"C")

#for cylinder
#given height =diameter
r=(1./(2*3.14))**(1./3.)#radius of the cylinder from volume of the cylinder v=3.14*r**2*h

 #solidification time for various shapes#