Ch-12, Organic materials, plastic, rubber, elastomers and wood

example-12.1 page no-382

In [3]:
from __future__ import division
#given
#degree of polymerization of styrene
DOP=10000
#formula of styrene= C8H8
#molecular weight of styrene monomer
Mm=12*8+1*8
#molecular weight of polymer
Mp=DOP*Mm
print "the molecular weight of styrene polymer is %d"%(Mp)
the molecular weight of styrene polymer is 1040000

example-12.2 page no-382

In [7]:
#given
#degree of polymerization of teflon
DOP=100000
#chemical formula of teflon is C2F4
#molecular weight of monomer teflon
Mm=2*12+4*19
#molecular weight of teflon polymer
Mp=DOP*Mm
#molecular weight of polythene monomer i.ee C2H4
MmP=2*12+4*1
#molecular weight of polythene polymer
MpP=DOP*MmP
print "molecular weight of PTFE anf Polythene are %d and %d"%(Mm,MpP)
#ratio of molecular weight of PTFE and Polythene
R=Mp/MpP
print "the ration of molecular weight of PTFE and Polythene having same DOP is %0.3f"%(R)
molecular weight of PTFE anf Polythene are 100 and 2800000
the ration of molecular weight of PTFE and Polythene having same DOP is 3.571

example-12.3 page no-396

In [5]:
#given
#the molecular weight of polyisoprene monomer
Mm=68  #gm
#after vulcanisation with sulphur, it is observedthat the 2 molecules of isoprene monimer require 2 molecules of sulphur
#hence for full cross linking ,(68*2) gm of isoprene requires (32*2)gm of sulphur. therefore 68kg of isoprene requires
M=32*2*68/68/2  #kg of sulphur
print "the weight of sulphur required for cross link polymerization of polyisoprene is %d of sulphur"%(M)
print "the fully cross linked product will be EBONITE"
the weight of sulphur required for cross link polymerization of polyisoprene is 32 of sulphur
the fully cross linked product will be EBONITE

example-12.4 page no-396

In [6]:
from __future__ import division
#given
#molecular weight of butdiene,isoprene,sulhur and carbon black are
MB=4*12+6*1
MI=68
MS=32
MC=12
#percentages of diiferent constituents in rubber
PB=27/MB
PI=51/MI
PS=16/MS
PC=6/MC
#percentage of coss linking
percent=PS/(PI+PB)*100
print "the percentage of cross linking is %d"%(percent)
the percentage of cross linking is 40