Chapter 24 - Refrigeration

Example 1 - Pg 461

In [1]:
#calculate the cop in both cases and also the piston displacement
#initialization of varaibles
print '%s' %("From tables,")
h1=611.8 #B/lb
h2=704.4 #B/lb
h3=127.4 #B/lb
h4=h3
T2=460. #R
T1=76+460. #R
W=10000. #B/hr
e=0.7
#calculations
Qe=h1-h4
Wc=h2-h1
CP=Qe/Wc
CP2=T2/(T1-T2)
w=W/(Qe*60.)
v1=9.116 #cu ft/lb
PD=w*v1/(e)
#results
print '%s %.2f' %("Coefficient of performance in case 1 = ",CP)
print '%s %.2f' %("\n Coefficient of performance in case 2 = ",CP2)
print '%s %.2f %s' %("\n Piston displacement =",PD,"cu ft/min")
From tables,
Coefficient of performance in case 1 =  5.23

 Coefficient of performance in case 2 =  6.05

 Piston displacement = 4.48 cu ft/min