Chapter 10 Nuclear Fission and Fusion

Example 10.1 Page no 351

In [7]:
#Given
c=3*10**8                       #m/s
m=3.6*10**-3                   #Kg
a=36000

#Calculation
E=m*c**2
E1=E/(a*10**3)

#Result
print"Energy is", E1*10**-6,"*10**7 Kilo watt-hrs"

Energy is 9.0 *10**7 Kilo watt-hrs

Example 10.2 Page no 352

In [16]:
#Given
mn=1.6747*10**-27
mp=1.6725*10**-27
me=9*10**-31
c=3*10**8
e=1.6*10**-19

#Calculation
m=mn-(mp+me)
E=(m*c**2)/e

#Result
print"Energy produced is", round(E*10**-6,2),"Mev"

Energy produced is 0.73 Mev

Example 10.3 Page no 352

In [28]:
#Given
P=3.2*10**7                   #Watts
e=1.6*10**-13
E1=200.0
a=1000
N=6.0*10**23
A=235

#Calculation
E=P/e
n=E/E1
n1=n*a*3600
m=n1*A/N

#Result
print"Number of fission occuring in the reactor/sec is", n
print"Mass of U235 used in 1000 hrs is",m*10**-3,"Kg"

Number of fission occuring in the reactor/sec is 1e+18
Mass of U235 used in 1000 hrs is 1.41 Kg