#Given
u=15.64
#Calculation
import math
a=math.log(0.5)**2/u
#Result
print"Linear absorption thickness is", round(a,3),"m"
#Given
V0=1.5*10**5 #volts
r=0.01 #cm
b=1 #cm
#Calculation
import math
E=V0/(math.log(10)*(math.log(b/r)))
#Result
print"Electric field is", round(E*10**-4,2),"*10**4 V/cm"
#Given
l=15.7 #eV
l1=7.8*10**-6 #m
b=0.05/2.0 #m
a=0.00006 #m
q=2.3026
#Calculation
import math
V=((l*a*q)/l1)*math.log10(b/a)
#Result
print"The voltage that must be applied to just produce an avalanche is",round(V,0),"volts"