# Chapter 10: AC Performance : Bandwidth, Slew rate and Noise¶

### Example 10.1 Page No 277¶

In [1]:
#Given
t=0.35       #rise time

#calculation
B=0.35/t    #Bandwidth

#result
print"Bandwidth is",B,"MHz"

Bandwidth is 1.0 MHz


### Example 10.2 Page No 277¶

In [2]:
#Given
t=0.35       #rise time

#calculation
B=0.35/t    #Bandwidth
gain=B

#result
print"Openloop Voltage gain  is",gain

Openloop Voltage gain  is 1.0


### Example 10.3 Page No 277¶

In [3]:
#Given
B1=10**6       #Hz
B2=100*10**3   #Hz

#calculation
gain=B1/B2

#Result
print"As frenquency goes down by a factor 10, Gain rise sby same which is",gain

As frenquency goes down by a factor 10, Gain rise sby same which is 10


### Example 10.4 Page No 278¶

In [4]:
#Given
B=1.5       #Mhz
f=1         #KHz

#Calculation
gain=B*1000/f

#Result
print"Open loop Voltage gain  is",gain

Open loop Voltage gain  is 1500.0


### Example 10.5 Page No 279¶

In [6]:
#Find the actual gain

#Given
Acl=100.0        #Ideal Dc cloesd loop gain
Aol1=10000.0
Aol2=1000.0
Aol3=100.0
Aol4=10.0
Aol5=1.0

#Calculation  (a)
#For a noninverting amplifier
a1=Acl                                               #ideal gain, a=(Rf+Ri)/Ri
actualAcl1=a1/((1+1*a1/Aol1))
#For the inverting amplifier
a2=101                                               #gain
actualAcl1_=-a1/(1+1*a2/Aol1)

# (b)
#For a noninverting amplifier
a1=Acl                                               #ideal gain, a=(Rf+Ri)/Ri
actualAcl2=a1/(1+1*a1/Aol2)
#For the inverting amplifier
a2=101                                               #gain
actualAcl2_=-a1/(1+1*a2/Aol2)

#(c)
#For a noninverting amplifier
a1=Acl                                               #ideal gain, a=(Rf+Ri)/Ri
actualAcl3=a1/(1+1*a1/Aol3)
#For the inverting amplifier
a2=101                                               #gain
actualAcl3_=-a1/(1+1*a2/Aol3)

#(d)
#For a noninverting amplifier
a1=Acl                                               #ideal gain, a=(Rf+Ri)/Ri
actualAcl4=a1/(1+1*a1/Aol4)
#For the inverting amplifier
a2=101                                               #gain
actualAcl4_=-a1/(1+1*a2/Aol4)

#(e)
#For a noninverting amplifier
a1=Acl                                               #ideal gain, a=(Rf+Ri)/Ri
actualAcl5=a1/(1+1*a1/Aol5)
#For the inverting amplifier
a2=101                                              #gain
actualAcl5_=-a1/(1+1*a2/Aol5)

#Result
print"(a)Actual gain in noninverting amplifier is",round(actualAcl5,2)
print"Actual gain in inverting amplifier is",round(actualAcl5_,2)
print"(b)Actual gain in noninverting amplifier is",round(actualAcl4,2)
print"Actual gain in inverting amplifier is",round(actualAcl4_,2)
print"(c)Actual gain in noninverting amplifier is",round(actualAcl3,2)
print"Actual gain in inverting amplifier is",round(actualAcl3_,2)
print"(d)Actual gain in noninverting amplifier is",round(actualAcl2,2)
print"Actual gain in inverting amplifier is",round(actualAcl2_,2)
print"(e)Actual gain in noninverting amplifier is",round(actualAcl1,0)
print"Actual gain in inverting amplifier is",round(actualAcl1_,2)

(a)Actual gain in noninverting amplifier is 0.99
Actual gain in inverting amplifier is -0.98
(b)Actual gain in noninverting amplifier is 9.09
Actual gain in inverting amplifier is -9.01
(c)Actual gain in noninverting amplifier is 50.0
Actual gain in inverting amplifier is -49.75
(d)Actual gain in noninverting amplifier is 90.91
Actual gain in inverting amplifier is -90.83
(e)Actual gain in noninverting amplifier is 99.0
Actual gain in inverting amplifier is -99.0


### Example 10.6 Page No 283¶

In [6]:
#Given
Ri=10.0      #Kohm
Rf=Ri
B=10**6    #Hz

#Calculation
#(a)
Acl1=-Rf/Ri
fh1=B/((Ri+Rf)/Ri)

#(b)
ACl2=(Ri+Rf)/Ri

#(c)
Acl3=1    #Voltage follower gain
Rf2=0
Ri2=1
fh2=B/((Ri2+Rf2)/Ri2)

#Resilt
print"(a)The voltage gain is",Acl1
print"bandwidth is",fh1/1000,"khz"
print"(b)The voltage gain is",ACl2
print"(c)The voltage gain is",Acl3
print"bandwidth is",fh2/1000000,"Mhz"

(a)The voltage gain is -1.0
bandwidth is 500.0 khz
(b)The voltage gain is 2.0
(c)The voltage gain is 1
bandwidth is 1 Mhz


### Example 10.7 Page No 285¶

In [7]:
#Given
V=10            #V
slewrate=0.5    #per microsecond

#Calculation
t=V/slewrate

#Result
print"The time taken is",t,"microsecond"

 The time taken is 20.0 microsecond


### Example 10.8 Page No 286¶

In [7]:
#Given
slewrate=0.5    #per microsecond
V1=10.0          #Peak voltage
V2=1

#Calculation
fmax1=slewrate*1000/(6.28*V1)
fmax2=slewrate*1000/(6.28*V2)

#Result
print"(a)maximum frenquency is",round(fmax1,1),"KHz"
print"(b)maximum frenquency is",round(fmax2,0),"KHz"

(a)maximum frenquency is 8.0 KHz
(b)maximum frenquency is 80.0 KHz


### Example 10.9 Page No 287¶

In [11]:
#Given
B1=500         #Khz, bandwidth
gain1=-1        #Gain for inverting amplifier
gain2=2        #Gain for non-inverting amplifier
slewrate=0.5   #per micros
V=10           #V

#Calculation
Vopmax=slewrate*10**6/(6.28*B1*10**3)
fmax=slewrate*1000/(6.28*V)

#Result
print"Maximum operating voltage is",round(Vopmax*1000,1),"mV"
print"maximum frenquency is",round(fmax,0),"Khz"

Maximum operating voltage is 159.2 mV
maximum frenquency is 8.0 Khz