from math import exp k=0.025 #in Electron Volts E=0.4 #in Electron Volts (The difference between Ec & Ed) Q=(10**8) # A given Constant in per second j=E/k O=Q*exp(-j) #Where O is the required probability O=round(O,2) Q1=1/O Q1=round(Q1,2) print "The probability of Escape per second of the trapped Electron "+str(O)+" /s" print "The Luminescence Lifetime is "+str(Q1)+" seconds"
The probability of Escape per second of the trapped Electron 11.25 /s The Luminescence Lifetime is 0.09 seconds
from math import degrees from math import asin n1=3.6 #For a Given GaAs/Air Interface n2=1 #For Air #Using Equation 4.14 n3=n1-n2 n4=n1+n2 n6=(n3/n4)**2 n5=(n2/n1)**2 F=0.25*(n5)*(1-n6) #Where F is the Fractional Transmission for Isotropic Radiation Originating F=round(F,3) theta=degrees(asin(1/n1)) #Critical Angle in Degrees theta=round(theta,0) print "The Fractional Tranmission for Isotropic Radiation originating inside GaAs is "+str(F) print "The Critical Angle which might explain the Low efficiency for the interface is "+str(theta)+" Degrees"
The Fractional Tranmission for Isotropic Radiation originating inside GaAs is 0.013 The Critical Angle which might explain the Low efficiency for the interface is 16.0 Degrees
%matplotlib inline import math from matplotlib.pyplot import plot,suptitle,xlabel,ylabel d=0.2*(10**-3) #Chip Diameter in meter d1=1 #Distance in Meter l=550*(10**-9 ) #Wavelength in Meter q=0.001 #External Quantam Efficiency i=50*(10**-3) #Operational Current h=6.6*(10**-34)#Plancks Constant c=3*(10**8)#Speed of Light e=1.6*(10**-19) theta=(d/2) #Whence theta is the angle emitting area subtends and is less than 1 print "Emitting Area subtends an angle Theta ="+str(theta) print "Since theta is less than one, it acts as a Point Source" W=((h*c)/l)*q*(i/e) #Where W is the total Radiant Power in terms of W W=round(W,6) print "The Total Radiant Power is "+str(W)+" W" #From the above graph l1=600 #Average Luminousity print "Observing from the below graph at 550 nm" lf=W*l1 #Where lf is the lumnious flux from the source lf=round(lf,3) print "The Luminous Flux from the source is"+str(lf)+" lm" li=lf/(2*3.14)#Where li is the luminous intensity at normal incidence since flux is distributed over angle 2PI li=round(li,4) print "The Luminous Intensity is "+str(li)+" Candela" X = [400,500,555,600,650,700] V = [0.0,0.3,1.0,0.7,0.3,0.0] plot(X,V); xlabel("Wavelength in nm") ylabel("V") suptitle("Fig 1.24")
Emitting Area subtends an angle Theta =0.0001 Since theta is less than one, it acts as a Point Source The Total Radiant Power is 0.000112 W Observing from the below graph at 550 nm The Luminous Flux from the source is0.067 lm The Luminous Intensity is 0.0107 Candela
<matplotlib.text.Text at 0x3d68198>