import math
#initialisation of variables
t=10.0 #min
i=0.1 #amp
M=63.54 #gm moleˆ−1
n=2.0
F=96500 #amp−sec equivˆ−1
Mo=32.0 #g moleˆ−1
T=25.0 #C
R=0.08205 #l−atm degˆ−1 moleˆ−1
p=740.0
n1=4.0
#CALCULATIONS
m=t*60*i*M/(F*n)
V=t*60*i*Mo*R*(273+T)*760/(F*n1*Mo*p)
#RESULTS
m=round(m,4)
V=round(V,4)
print 'number of grams of copper deposited at cathode=',m,'gram'
print 'volume of oxygen liberated at anode=',V,'lit'
import math
#initialisation of variables
r=82.4 #ohms
k= 0.002768 #ohmˆ−1
R1= 326 #ohm
#CALCULATIONS
K= r*k
K1= (K/R1)
#RESULTS
K=round(K,4)
K1=round(K1,4)
print 'cell constant=',K,'cmˆ−1'
print 'specific conductance=',K1,'ohmˆ−1 cmˆ−1'
import math
#initialisation of variables
C= 0.005 #N
k= 6.997*10** -4 #ohmˆ−1 cmˆ−1
#CALCULATIONS
A= 1000*k/C
#RESULTS
print 'equivalent conductance=',A,'cmˆ2 equivˆ−1 ohmˆ−1'
import math
#initialisation of variables
AHcl= 426.1 #cmˆ2 equivˆ−1 ohmˆ−1
ANaC2H3O2= 91 #cmˆ2 equivˆ−1 ohmˆ−1
ANaCl= 126.5 #cmˆ2 equivˆ−1 ohmˆ−1
#CALCULATIONS
AHC2H3O2= AHcl+ANaC2H3O2 -ANaCl
#RESULTS
print 'equivalent conductance of acetic acid=',AHC2H3O2,'cmˆ2 equivˆ−1 ohmˆ−1'
import math
#initialisation of variables
Ke=48.15
Ki=390.6
c=0.001028 #N
#CALCULATIONS
a=Ke/Ki
K=a**2*c/(1-a)
#RESULTS
K=format(K, '.7f')
print 'ionisation constant=',K
import math
#initialisation of variables
i=0.00521 #amp
A=0.23 #cmˆ2
k=0.0129 #ohmˆ−1 cmˆ−1
t=67 #min
l=4.64 #cm
#CALCULATIONS
r=i/(A*k)
uK=l/(t*60*r)
#RESULTS
r=round(R,4)
uK=round(uK,4)
print 'electrical field strength=',r,'volts cmˆ−1'
print 'mobility of potassium ion=',uK,'cmˆ2 volt ˆ−1 cmˆ−1'
import math
#initialisation of variables
C=0.1 #N
F=96500 # coloumbs
mna=42.6*10** -5 #cmˆ2 volt secˆ−1
mcl=68*10**-5 # cmˆ2 c o l t secˆ−1
#CALCULATIONS
k=F*(mna+mcl)*C/1000
#RESULTS
k=round(k,4)
print 'specific conductance of sodium chloride=',k,' ohmˆ−1 cmˆ−1'
import math
#initialisation of variables
V=4.9 #faradayˆ−1
c=0.1 #N
#CALCULATIONS
TK=V*c
Tcl=1-TK
#RESULTS
print 'transference number of chlorine=',Tcl
import math
#initialisation of variables
Mc=63.54 #gms
n=2.0
mc=0.3 #gms
mc1=1.43
mc2=1.2140
#CALCULATIONS
Me=Mc/n
Tc=((mc/Me)-((mc1 -mc2)/Me))/(mc/Me)
Ta=1-Tc
#RESULTS
print 'copper transference number=',Ta
import math
#initialisation of variables
Tn=0.820
Tn1=0.450
A=426.1
A1=91
#CALCULATIONS
l=Tn*A
l1=Tn1*A1
L=l+l1
#RESULTS
print 'A0 for acetic acid=',L
import math
#initialisation of variables
T=25.0 #C
n=2.0
F=96500.0 # coloumbs
R=8.316 #J moleˆ−1 Kˆ−1
a=76.2*10 -5
a1=79*10**-5
A=155.2*10** -5
#CALCULATIONS
D0=n*a*a1*R*(273+T)*10**-6/(F*A)
#RESULTS
print 'limiting diffusion cooeficient=',format(D0, '.8f'),'cmˆ2 secˆ−1'