In [2]:

```
#Given
f= 450.0*10**6
#Calculation
lamda = 984/f
len =0.1*lamda
#Result
print"feet long conductors would be considered as the transmission line ",round(len*10**6,3),"ft"
```

In [4]:

```
#Given
lamda = 2.19
#Calculation
len = (3/8.0)*lamda
#Result
print"The pyhsical length of the transmission line ",round(len,2),"feet"
```

In [5]:

```
#Given
len = 165
attn_100ft = 5.3
pin = 100
attn_ft = 5.3/100.0
#Calculation
total_attn = attn_ft * len
pout = pin *0.1335
#Result
print"The total attenuation of the cable is ",total_attn,"dB"
print"Output power is ",pout,"W"
```

In [7]:

```
#Given
len =150
C =13.5
Z0 =93
f =2.5*10**6
attn_100ft =2.8
#Calculation
L =C*Z0**2
td =(L*C)**0.5
theta = ((360)*188.3)/(1/f)
attn_ft = attn_100ft/100.0
total_attn = attn_ft*150
print"(a) The load impedance required to terminate the the line to avoid the reflections is %d ohm",Z0
print"(b) The equivalent inductance per feet is ",L/10**3,"nh"
print"(c) The time delay introduced by the cable per feet is ",td/10**3,"ns"
print"(d) The phase shift occurs in degrees for the 2.5 Mhz sine wave is ",theta/10**9
print"(e) The total attenuation is ",total_attn,"db"
```

In [7]:

```
#Given
vmax= 52.0
vmin= 17.0
Z0 = 75
#calculation
SWR = vmax/vmin
ref_coeff = (vmax-vmin)/(vmax+vmin)
Zl1 = Z0*SWR
Zl2 = Z0/SWR
#Result
print"(a) The standing wave ratio is ",round(SWR,2)
print"(b) Reflection coefficient is ",round(ref_coeff,2)
print"The value of resistive load is ",round(Zl1,2),"ohm or",round(Zl2,2),"ohm"
```

In [9]:

```
#Given
SWR =3.05
ref_pwr =0.2562
pin =30
#calculation
pout = pin -(pin*((SWR-1)/(SWR+1))**2)
#Result
print"The output power of the cable is ",round(pout,3),"W"
```

In [13]:

```
#Given
C =4*10**-12
f =800*10**6
diele = 3.5
h = 0.0625
w = 0.13
t = 0.002
#Calculation
import math
Z0 = 38.8*math.log(0.374/0.106)
Xc = 1/(6.28*f*C)
#Result
print"The charecteristics impedance of the transmission line is ",round(Z0,1),"ohm"
print"The reactance of the capacitor is ",round(Xc,2),"ohm"
```

In [19]:

```
#Given
lamda = (984/800.0)
lamda_8 =lamda/8.0
#Calculation
len = lamda_8*12*(1/3.6**0.5)
#Result
print"The length of the transmission line is ",round(len,3)
```