In [1]:

```
#given
E=5000 #Intensity of electric field in N/C
d=0.02 #Distance in m
e=(1.6*10**-19) #Charge of the electron in C
m=(9.1*10**-31) #Mass of the electron in kg
#Calculations
import math
v=math.sqrt(2*e*E*d/m)/10**6
#Output
print"Speed of the electron is ",round(v,2),"*10**6 m/s"
```

In [2]:

```
#given
v=(5*10**6) #Velocity of the electron in m/s
E=2000 #Intensity of electric field in N/C
d=0.06 #Distance in m
e=(1.6*10**-19) #Charge of the electron in C
m=(9.1*10**-31) #Mass of the electron in kg
#Calculations
y=((-e*E*d**2)/(2*m*v**2))*100
#Output
print"Vertical displacement of the electron when it just leaves the electric field is ",round(y,2),"cm"
```

In [4]:

```
#given
v=(4*10**5) #Velocity of the positively charged particle in m/s
E=300 #Intensity of electric field in N/C
e=(1.6*10**-19) #Charge of the positively charged particle in C
m=(1.67*10**-27) #Mass of the positively charged particle in kg
q=35 #Angle made by the particle in degrees
#Calculations
import math
t=((v*math.sin(q*3.14/180.0)*m)/(e*E))/10**-6
#Output
print"Time required by the particle to reach the maximum height in the electric field is ",round(t,2),"micro s"
```

In [6]:

```
#given
r=0.3 #Radius of circular orbit in m
B=0.38 #Magnetic field strength in T
e=(1.6*10**-19) #Charge of the proton in C
m=(1.672*10**-27) #Mass of the proton in kg
#Calculations
v=((e*B*r)/m)/10**6
#Output
print"Orbital speed of the proton is ",round(v,0),"*10**6 m/s"
```

In [2]:

```
#given
e=(1.6*10**-19) #Charge of the proton in C
m=(1.67*10**-27) #Mass of the proton in kg
B=0.8 #Magnetic field strength in T
v=(4*10**6,3*10**6) #Velocity of charged particle in vxi+vyj form in m/s
#Calculations
p=(v[0]*2*3.14*m)/(e*B)
R=(m*v[1])/(e*B)
#Output
print"The pitch of the helix is ",round(p,3),"m"
print"Radius of the trajectory is ",round(R,3),"m"
```