# Chapter 17: Introduction to Elementary Particles¶

## Example 17.1, Page 625¶

In [1]:
#Variable declaration
h=1.05*10**-34#j-s
M=1.7*10**-27#in kg
r=2*10**-15#in m

#Calculations
K=(h**2)/(M*r*r)
s=K* 6.24150647996E+12#converting to Mev
K_total_cm=2*s
k_incident=2*K_total_cm

#Result
print "The kinetic energy of incident nucleon is %d Mev"%k_incident

The kinetic energy of incident nucleon is 40 Mev


## Example 17.3, Page 635¶

In [2]:
#Variable declaration
h=1*10**-34#j-s
r=2*10**-15#m
c=3*10**8#m/s

#Calculations
m_pi=h/(r*c)

#Result
print "The value of m pi is %.e kg"%m_pi
#Answer difference is because of round off

The value of m pi is 2e-28 kg


## Example 17.5, Page 646¶

In [3]:
#Calculations&Results

#For Ao
Tz=(1-1)/2
print "The value of Tz for Ao is %.f "%Tz

#For K+
Q=1
B=0
S=1
Tz=1-0.5
print "The value of Tz for K+ is %.1f "%Tz

#For K-
Q=-1
B=0
S=-1
Tz=-1+0.5
print "\nThe value of Tz for K- is %.1f"%Tz

#For Ko
Q=0
B=0
S=1
Tz=-0-0.5
print "\nThe value of Tz for Ko is %.1f"%Tz

#For Ko_dash
Tz=0+0.5
print "\nThe value of Tz for Ko- is %.1f"%Tz

The value of Tz for Ao is 0
The value of Tz for K+ is 0.5

The value of Tz for K- is -0.5

The value of Tz for Ko is -0.5

The value of Tz for Ko- is 0.5