Chapter 19 :The Nucleus

Example 19.4 , Page no:114

In [1]:
import math
from __future__ import division
 
#initialisation of variables
a=((0.7552*34.969)+(0.2447*36.966));
 
#RESULTS    
print"Atomic mass of chlorine =",round(a,3);

Atomic mass of chlorine = 35.454

Example 19.5 , Page no:115

In [2]:
import math
from __future__ import division
 
#initialisation of variables
delm=(8.0626+8.0693)-15.9949; #in u

#CALCULATIONS
E=delm*931; #calculating binding energy in MeV

#RESULTS
print"Binding Energy in MeV =",round(E,3);

Binding Energy in MeV = 127.547

Example 19.6 , Page no:115

In [3]:
import math
from __future__ import division
 
#initialisation of variables
m0=10.07825+10.08665; #in u

#CALCULATIONS
delm=160.6/931; #calculating mass eqvi. of 160.6 MeV
delm1=(m0-delm);

#RESULTS
print"Atomic Mass in u =",round(delm1,3);

Atomic Mass in u = 19.992

Example 19.10 , Page no:115

In [4]:
import math
from __future__ import division
 
#initialisation of variables
m=0.001; #mass in kg
c=3*10**8; #velocity in m/sec 
p=10**8; #power in Watt
t=24; #time in hr/day

#CALCULATIONS
E=m*c*c; #Eintstein equation
M=(p*3600*t)/E; #calculating mass of U required
M1=E/(7822*4185); #calculating mass of coal required

#RESULTS
print"Energy in Joule =",round(E,3);
print"Mass of U required in kg/day =",round(M,3);
print"Mass of coal required in kg/day =",round(M1,3);

Energy in Joule = 9e+13
Mass of U required in kg/day = 0.096
Mass of coal required in kg/day = 2749344.969