Chapter 7: Lattice or Atomic Vibrations

Exa 7.1

In [1]:
from __future__ import division
import math
 # Python Code Ex7.1 Cut-off frequency of 
 #the linear lattice of a solid: Page-238 (2010)
 
 
#Variable declaration
 
v = 3e+03;                            # Velocity of sound in the solid, m/s
a = 3e-010;                             # Interatomic distance, m

# Calculation

 # As cut-off frequency occurs at k = %math.pi/a and
# k = 2*%math.pi/lambda, this gives
lamb = 2*a;                           # Cut-off wavelength for the solid, m
f = v/lamb; # Cut-off frequency (v = f*lambda) for the linear lattice, hertz


#Result

print"\nThe cut-off frequency for the linear lattice of a solid =",f,"Hz"
 
The cut-off frequency for the linear lattice of a solid = 5e+12 Hz

Exa 7.2

In [1]:
from __future__ import division
import math
 # Python Code Ex7.2 Comparison of frequency of waves in 
 #a monoatomic and diatomic linear systems: Page-238 (2010)
 
 
  
#Variable declaration
 
a = 2.5e-010;         # Interatomic spacing between two identical atoms, m
v_0 = 1e+03;                             # Velocity of sound in the solid, m/s
lamb = 10e-010;                       # Wavelength of the sound wave, m
omega_min = 0;   # Angular frequency of acoustic waves at k = 0, rad per sec



#Calculation and Results

# Angular frequency of sound wave in a monoatomic lattice, rad per sec
omega = v_0*2*math.pi/lamb;              
print"\nThe frequency of sound waves in a monoatomic lattice ="
print round((omega*10**-12),2)*10**12,"rad/sec"
 # For acoustic waves in a diatomic lattice (M = m), 
#the angular frequency, omega = 0 at k = 0 and
 # omega = (2*K/m)**(1/2)    --- (i)    at k = %math.pi/(2*a)
 # As v0 = a*(2*K/m)**(1/2)  --- (ii)
 # From (i) and (ii), we have
# Angular frequency of acoustic waves at k = %math.pi/(2*a), rad per sec
omega_max = v_0/a;            
print"\n\nThe frequency of acoustic waves wave in a diatomic lattice :\n  "
print omega_min," rad/sec for k = 0 \n "
print omega_max," rad/sec k = ", round(math.pi/(2*a)) 
 # For optical waves in a diatomic lattice (M = m), the angular frequency 
 # omega = sqrt(2)*(2*K/m)**(1/2)    --- (iii)    at k = 0
 # As v0 = a*(2*K/m)**(1/2)    --- (iv)
 # From (iii) and (iv), we have
 # Angular frequency of optical waves at k = 0, rad per sec
omega_max = (2)**0.5*v_0/a;             
 # For optical waves in a diatomic lattice (M = m), the angular frequency 
 # omega = (2*K/m)**(1/2)    --- (iii)    at k = %math.pi/(2*a)
 # As v0 = a*(2*K/m)**(1/2)    --- (iv)
 # From (iii) and (iv), we have
# Angular frequency of optical waves at k = %math.pi/(2*a), rad per sec
omega_min = v_0/a;                      
print"\n\nThe frequency of optical swaves wave in a diatomic lattice :\n "
print round((omega_max*10**-12),2)*10**12," rad/sec for k = 0 \n "
print omega_min," rad/sec for k =",round( math.pi/(2*a) ) 
 
The frequency of sound waves in a monoatomic lattice =
6.28e+12 rad/sec


The frequency of acoustic waves wave in a diatomic lattice :
  
0  rad/sec for k = 0 
 
4e+12  rad/sec k =  6283185307.0


The frequency of optical swaves wave in a diatomic lattice :
 
5.66e+12  rad/sec for k = 0 
 
4e+12  rad/sec for k = 6283185307.0

Exa 7.3

In [3]:
from __future__ import division
import math
 # Python Code Ex7.3 Reflection of electromagentic radiation
# from a crystal: Page-239(2010)


 
#Variable declaration
 

c = 3.0e+08;                 # Speed of electromagnetic wave in vacuum, m/s
a = 5.6e-010;                        # Lattice parameter of NaCl crystal, m
# Modulus of elasticity along [100] direction of NaCl, newton per metre square
Y = 5e+010;               
m = 23;                                 # Atomic weight of sodium, amu
M = 37;                                 # Atomic weight of chlorine, amu
amu = 1.67e-027;                        # Kg equivalent of 1 amu


#Calculation

# Force constant of springs when the extension along
# [100] direction is neglected, N/m
K = a*Y;                                
# The max. angular frequency of the reflected e.m. radiation, rad per sec
omega_plus_max = (2*K*(1/(M*amu)+1/(m*amu)))**(1/2);
 # The wavelength at which the e.m. radiation is strongly reflected, m
lamb = 2*math.pi*c/omega_plus_max;       


#Result

print"\nThe wavelength at which the electromagnetic radiation is"
print" strongly reflected by the crystal =",round((lamb*10**5),2)*10**-5,"m"
The wavelength at which the electromagnetic radiation is
 strongly reflected by the crystal = 3.88e-05 m