# Chapter9-Dilute Solutions¶

## Ex1-pg258¶

In [6]:
import math
##Intitalisation of variables

p1= 17.535 ##mm
p2= 17.226 ##mm
M= 100. ##gms
m1= 18.02 ##gms
m2= 18.04 ##gms
##CALCULATIONS
M= (-1.+(p1/(p1-p2)))*m1*m2/M
##RESULTS
print'%s %.2f %s'% ('Molecular weight of mannitol = ',M,' gms')
print'%s %.2f %s'% ('\n Correct Molecular weight of mannitol = ',M+1,' gms')

Molecular weight of mannitol =  181.22  gms

Correct Molecular weight of mannitol =  182.22  gms


## Ex2-pg262¶

In [5]:
import math
##Intitalisation of variables

dT= 0.170 ##C
M2= 60.06 ##gms
w1= 22.5 ##gms
w2= 0.45 ##gms
R= 1.987 ##cal
T= 100. ##C
lv= 539.9 ##cal g^-1
##CALCULATIONS
Kb= dT*M2*w1/(1000.*w2)
Kb1= R*(273.2+T)**2/(lv*1000.)
##RESULTS
print'%s %.2f %s'% ('Eleveation constant of water =  ',Kb,'')
print'%s %.2f %s'% ('\n Eleveation constant of water = ',Kb1,'')

Eleveation constant of water =   0.51

Eleveation constant of water =  0.51


## Ex3-pg265¶

In [4]:
import math
##Intitalisation of variables

Kf= 5.12
m= 0.911 ##gms
m1= 50. ##gms
dT= 0.603 ##deg
##CALCULATIONS
M2= Kf*1000.*m/(m1*dT)
##RESULTS
print'%s %.2f %s'% ('Molecular weight of carbon tetra chloride = ',M2,' gms')

Molecular weight of carbon tetra chloride =  154.70  gms


## Ex4-pg271¶

In [3]:
import math
##Intitalisation of variables

m= 4. ##gms
p= 6.4*10**-4 ##atm
T= 27. ##C
R= 0.082 ##lit atm deg^-1 mole^-1
##CALCULATIONS
M= R*(273.+T)*m/p
##RESULTS
print'%s %.2e %s'% ('Molecular weight of polymer = ',M,' gms')

Molecular weight of polymer =  1.54e+05  gms


## Ex5-pg277¶

In [2]:
import math
##Intitalisation of variables

v1= 18.10 ##cc
T= 100. ##C
p= 2.47 ##atm
L= 539.9 ##cal mole^-1 gm^-1
m= 18.02 ##gm
T1= 30. ##C
##CALCULATIONS
dT= v1*(273.2+T)**2*p*1.013*10**6/(L*m*4.184*10**7*(273.2+T1))
##RESULTS
print'%s %.2f %s'% ('Elevation of boiling point = ',dT,' degrees')

Elevation of boiling point =  0.05  degrees


## Ex6-pg280¶

In [1]:
import math
##Intitalisation of variables

dt= 0.0265 ##deg
c= 5.*10**-3 ##M
kf= 1.86 ##deg
##CALCULATIONS
i= dt/(c*kf)
##RESULTS
print'%s %.2f %s'% ('i of the solution = ',i,'')

i of the solution =  2.85