Chapter 12 : Fugacity and Activity¶

Example 12.1 Page No : 252¶

In [1]:
# Variables
p1 = 50 			#atm
p2 = 100 			#atm
p3 = 200 			#atm
p4 = 400 			#atm
p5 = 800 			#atm
p6 = 1000 			#atm
r1 = 0.979
r2 = 0.967
r3 = 0.971
r4 = 1.061
r5 = 1.489
r6 = 1.834

# Calculations
f1 = r1*p1
f2 = r2*p2
f3 = r3*p3
f4 = r4*p4
f5 = r5*p5
f6 = r6*p6

# Results
print  'fugacity of nitrogen gas  = %.2f atm'%(f1)
print  ' fugacity of nitrogen gas  = %.1f atm'%(f2)
print  ' fugacity of nitrogen gas  = %.1f atm'%(f3)
print  ' fugacity of nitrogen gas  = %.1f atm'%(f4)
print  ' fugacity of nitrogen gas  = %.f atm'%(f5)
print  ' fugacity of nitrogen gas  = %.f atm'%(f6)

fugacity of nitrogen gas  = 48.95 atm
fugacity of nitrogen gas  = 96.7 atm
fugacity of nitrogen gas  = 194.2 atm
fugacity of nitrogen gas  = 424.4 atm
fugacity of nitrogen gas  = 1191 atm
fugacity of nitrogen gas  = 1834 atm


Example 12.2 Page No : 258¶

In [2]:
# Variables
p1 = 50 			#atm
p2 = 100 			#atm
p3 = 200 			#atm
p4 = 400 			#atm
r1 = 0.98
r2 = 0.97
r3 = 0.98
r4 = 1.07

# Calculations
f1 = p1*r1
f2 = p2*r1
f3 = p3*r3
f4 = p4*r4

# Results
print  'fugacity of nitrogen gas  = %.f atm'%(f1)
print  ' fugacity of nitrogen gas  = %.f atm'%(f2)
print  ' fugacity of nitrogen gas  = %.f atm'%(f3)
print  ' fugacity of nitrogen gas  = %.f atm'%(f4)

fugacity of nitrogen gas  = 49 atm
fugacity of nitrogen gas  = 98 atm
fugacity of nitrogen gas  = 196 atm
fugacity of nitrogen gas  = 428 atm


Example 12.3 Page No : 260¶

In [3]:
# Variables
p = 3.66 			#atm
v = 6.01 			#litre mole**-1
T = 0    			#C
R = 0.082 			#lit-atm mole**-1 K**-1

# Calculations
f = p**2*v/(R*(273+T))

# Results
print  'fugacity of liquid chlorine  = %.2f atm'%(f)

fugacity of liquid chlorine  = 3.60 atm

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