Chapter 2 Indicators and display devices

Example 2.1 (a) Page no 27

In [1]:
#Given
N=100
W=20*10**-3                                #Width of the coil in m
A=30*10**-3                               #Depth of the coil in mm
B=0.1                                     #flux density in wb/m**2
I=10*10**-3                                 #current in A
K=2.0*10**-6                                #Nm/degree

#Calculation
T=B*A*W*I*N
x=T/K

#Result
print"The deflection torque is ",T,"m"
print"The deflection is ", x,"degree"
The deflection torque is  6e-05 m
The deflection is  30.0 degree

Example 2.1 (b) Page no 27

In [1]:
#Given
N=100
A=20*10**-3                               #m
d=30*10**-3                               #m
D=0.1                                     #Wb/m**2
t=30*10**-6                               #Nm

#Calculation
I=(t/(D*d*A*N))*10**3

#Result
print"The current through the moving coil is ", I,"mA"
The current through the moving coil is  5.0 mA