# Chapter 16 Reflection of light¶

## Exaple 16.1 Page no 890¶

In [5]:
#Given
HF=2
EF=1.9

#Calculation
L=0.5*HF
DB=0.5*EF

#Result
print"Maximum height of mirror is", L,"m"
print"Bottom edge of the mirror is",DB,"m"

Maximum height of mirror is 1.0 m
Bottom edge of the mirror is 0.95 m


## Example 16.2 Page no 890¶

In [14]:
#Given
u=-15.0                             #cm
f=-10                             #cm
o=2.0                              #cm

#Calculation
v=1/((1.0/f)-(1.0/u))
m=v/u
I=-m*o

#Result
print"Position of the image is", v,"cm"
print"Size of the image is",I,"cm"
print"Nature of the image isreal and inverted "

Position of the image is -30.0 cm
Size of the image is -4.0 cm
Nature of the image isreal and inverted


## Example 16.3 Page no 891¶

In [25]:
#Given
u=-10.0                       #cm
f=-15.0

#Calculation
v=1/((1/f)-(1/u))
m=-v/u

#Result
print"(i) Image position is", v,"cm"
print"(ii) Magnification is", m

(i) Image position is 30.0 cm
(ii) Magnification is 3.0


## Example 16.4 Page no 891¶

In [31]:
#Given
f=12.0
v=4.0

#Calculation
u=1/((1/f)-(1/v))
m=-v/u

#Result
print"(i) Object position is", u,"cm"
print"(ii) Magnification is", round(m,2)

(i) Object position is -6.0 cm
(ii) Magnification is 0.67


## Example 16.5 Page no 891¶

In [36]:
#Given
R=36                     #ohm

#Calculation
f=-R/2.0
u=(2*f)/3.0

#Result
print"Position of the object is", u,"cm"

Position of the object is -12.0 cm


## Example 16.6 Page no 892¶

In [40]:
#Given
R=20                  #cm

#Calculation
f=R/2.0
u=-f
v=-u/2.0

#Result
print"Position of the object is",u,"cm"
print"Position of the image is",v,"cm"

Position of the object is -10.0 cm
Position of the image is 5.0 cm


## Example 16.7 Page no 892¶

In [49]:
#Given
f=-15.0

#Calculation
u=(1/(1/f)/3.0)*4
v=u/2.0

#Result
print"Position of object is" ,u,"cm"
print"When the image is virtual",v,"cm"

Position of object is -20.0 cm
When the image is virtual -10.0 cm


## Example 16.8 Page no 892¶

In [58]:
#Given
R=30                      #ohm
u=-10.0
h1=5

#Calculation
f=R/2.0
v=1/((1/f)-(1/u))
h2=(-v*h1)/u

#Result
print"Position of the image is", v,"cm"
print"Size of the image is",h2,"cm"
print"The image is virtual"

Position of the image is 6.0 cm
Size of the image is 3.0 cm
The image is virtual


## Example 16.9 Page no 893¶

In [66]:
#Given
f=-10.0                            #cm
u=-25.0                             #cm
h1=3

#Calculation
v=1/((1/f)-(1/u))
h2=(-v*h1)/u
A=h2**2

#Result
print"Area enclosed by the image of the wire is", A,"cm**2"

Area enclosed by the image of the wire is 4.0 cm**2