#Given
V=1000
d=10.0*10**-3
m=4.8*10**-15
g=10
e=1.6*10**-19
#Calculation
E=V/d
q=m*g/E
n=q/e
#Result
print"The number of electrons on the drop ", n
#Given
e=1.6*10**-19
E=3*10**4
m=9.0*10**-31
y1=4*10**-2
m2=1.67*10**-27
#Calculation
a=e*E/m
t=math.sqrt((2*y1)/a)
a2=e*E/m2
t2=math.sqrt((2*y1)/a2)
#Result
print"Time t1=", round(t*10**9,1)*10**-9,"S","\nTime t2=",round(t2*10**7,2)*10**-7,"S"
#Given
r=1 #m
m=9*10**9
q=500*10**-6
r1=0.3 #m
#Calculation
E=m*q/r**2
E2=m*q/r1**2
#Result
print"(i) Electric field intensity from the centre of the sphere ",E*10**-6,"10**6","N/C"
print"(ii) Electric field intensity at the surface of the sphere is ",E2*10**-7,"10**7 N/C"
#Given
q=2*10**-8
E=2*10**4
m=80*10**-6
g=9.8
#Calculation
import math
a=q*E/(m*g)
b=math.atan(a)*180/3.14
T=(q*E/(math.sin(b*3.14/180.0)))*10**-4
#Result
print"The angle is ", round(b,0),"degree"
print"Tension in the thread of the pendulum is ", round(T*10**8,2),"*10**-4 N"
#Given
m=9*10**9
r=0.707
q=5*10**-6
#Calculation
import math
E=m*q/r**2 #along AO
E2=m*q/r**2 #along BO
E3=m*q/r**2 #along OD
E11=E+E2
E12=E2+E3
I=(2*E11*r)*10**-4
#Result
print"Electric field at the centre of the sphere is ",round(I,2),"*10**4 N/C"
#Given
q=5*10**-9
x=0.15 #m
r=0.1 #m
a=9*10**9
#Calculation
E=(a*q*x)/((r**2+x**2))**1.5
#Result
print"Intensity of the electric field is ", round(E,0),"N/C"
#Given
m=10**-3
F=1
v0=20
v=0
#Calculation
a=-F/m
s=v**2-v0**2/(2.0*a)
#Result
print"The distance is ", s,"m"
#Given
m=9*10**9
q1=1/3.0*10**-7
r=5*10**-2
F=58.8*10**-3
#Calculation
q2=F*r**2/(q1*m)
#Result
print"Charge is ", q2,"C"
#Given
E=4*10**5 #V/m
q=3.2*10**-19
a=2.4*10**-10
#Calculation
import math
p=q*a
W=p*E*(1-(math.cos(180*180/3.14)))
#Result
print"Work done is ", W
#Given
q=16*10**-19
a=3.9*10**-12
E=10**5
#Calculation
p=q*a
U=-p*E
#Result
print"(i) The electric dipole moment ", p,"Cm"
print"(ii) Potential energy of dipole in the stable equilibrium position ",U,"J"
#Given
q=20*10**-6
a=10**-2
m=9*10**9
r=0.1
#Calculation
p=q*a
E=m*2*p/r**3
#Result
print"Electric field intensity is ", E*10**-5,"*10**5 N/C"
#Given
E=4*10**5
q=1*10**-6
a=3*10**-2
#Calculation
t=q*a*E
#Result
print"Maximum torque on the dipole is ", t*10**2,"*10**-2 Nm"
#Given
q=1*10**-6
a=2*10**-2
E=10**5
#Calculation
p=q*a
W=2*p*E
#Result
print"Work done in the rotation is ", W*10**3,"*10**-3 J"
#Given
q=2*10**-6
a=0.1
m=9*10**9
r=0.5
#Calculation
p=q*a
E=m*p/r**3
#Result
print"Electric field intensity is ",E*10**-4,"*10**4 N/C"
#Given
qa=2.5*10**-7
qb=-2.5*10**-7
a=15
b=15
#Calculation
q=qa+qb
C=(a+b)*10**-2
E=qa*C
#Result
print"Total charge is ", q,"\nElectric dipole moment of the system is ",E,"Cm"
#Given
p=2*10**-8
m=9*10**9
r=1.0
#Calculation
import math
b=3*math.cos(60*3.14/180.0)**2+1
a=p*math.sqrt(b)
E=(m*a)/r**3
#Result
print"Magnitude of electric intensity is", round(E,1),"N/C"
#Given
p=5*10**-8
m=9*10**9
r=0.15
#Calculation
E=m*2*p/r**3
E1=m*p/r**3
print"(i) Electric field along AB is ", round(E*10**-5,2),"*10**5 N/C"
print"(ii) Electric field along BA is ", round(E1*10**-5,2),"*10**5 N/C"